NCERT Solutions For Class 12 Chemistry Chapter 13: This Class 12 Chemistry Chapter 13 teaches that amines constitute an important organic compound component. These are derived by replacing one or more hydrogen atoms of ammonia molecule by alkyl/aryl group(s). This is a crucial chapter. Therefore, candidates have to practice this chapter thoroughly to score good marks. Therefore, it is important that you understood all the concepts mentioned in this chapter. For this, we will introduce you to the NCERT Solutions For Class 12 Chemistry Chapter 13 – Amines here.
Please note that these solutions are created by the academicians and top educationalists of Embibe. They have solved every question step-by-step so that students can easily understand the concepts. Moreover, you can follow these solution PDFs at the time of revising and practicing. So keep on scrolling down the section and download the NCERT Solution for Class 12 Chemistry Chapter 13 for free.
NCERT Solutions For Class 12 Chemistry Chapter 13 Amines
The topics and sub-topics of NCERT Class 12 Chemistry Chapter 13 Amines will help you in your CBSE Class 12 Chemistry Preparation. The topics and sub-topics of this topic will aid you in preparing well for the CBSE Exam. This will also help you in understanding the topics under NCERT Class 12 Chemistry Chapter 13:
|13.1||Structure of Amines|
|13.4||Preparation of Amines|
|13.7||Method of Preparation of Diazonium Salts|
|13.10||Importance of Diazonium Salts in the Synthesis of Aromatic Compounds|
Chapter Description Of Class 12 Chemistry Chapter 13 – Amines
This chapter highlights the importance of amines as derivatives of ammonia comprising of a pyramidal structure. You will get to know about some of the important preparation methods of amines. This clearly gets you an idea of their chemical properties.
Moreover, in this chapter, you will learn about diazonium salts and their preparation method. This will also help you understand the importance of these salts in the synthesis of aromatic compounds. Finally, solving the NCERT questions of Chapter 13 will further assist you in clearing any confusion you might have on this topic.
NCERT Solutions For Class 12 Chemistry Chapter 13 PDF
Students can feel free to download the NCERT Class 12 Chemistry Chapter 13 solutions from the below link. The solution files are available in PDF format so that students can go through them anytime. The solutions prepared by our experts follow every NCERT guidelines, which will help you improve in this chapter. We have mentioned some of the examples below, which will give you an idea about how we have solved these Chemistry Chapter 13 NCERT questions.
Q: An aromatic compound ‘A’ on treatment with aqueous ammonia and heating forms compound ‘B’ on heating with Br2, and KOH forms a compound ‘C’ of molecular formula C6H7N. Write the structures and IUPAC names of compounds A, B, and C.
A: It is given in the question the compound ‘C’ having the molecular formula, C6H7N is formed by heating compound ‘B’ with Br2 and KOH. Reaction with Br2 or KOH is a Hoffman bromamide degradation reaction and is given by an amide. The formed product is an amine (one carbon down amide). Therefore, compound ‘B’ is an amide, and compound ‘C’ is an amine. Therefore, the only amine having the molecular formula, C6H7N is aniline, (C6H5NH2).
Therefore, compound ‘B’ must be benzamide (C6H5CONH2)
Further, benzamide is formed by heating compound ‘A’ with aqueous ammonia. Therefore, compound ‘A’ must be benzoic acid. Every associated reaction is given in the NCERT Solutions For Class 12 Chemistry Chapter 13 PDF.
Q: Why are amines less acidic than alcohols of comparable molecular masses?
A: Amines undergo protonation to give amide ion
R − NH2 → R + NH2– + H+
Similarly, alcohol loses a proton to give alkoxide ions.
R − OH → R − O− + H+
Acidic strength ∝ stability of conjugate base or anion
Stability of conjugate base or anion ∝ negative charge density on anion ∝ electronegativity of an atom.
In an amide ion, the negative charge is on the N-atom, whereas, in an alkoxide ion, the negative charge is on the O-atom. Since O is more electronegative than N, O can accommodate the negative charge more easily than N. As a result; the amide ion is less stable than the alkoxide ion, i.e., the conjugate base amide is less stable than alkoxide ion. Hence, amines are less acidic than alcohols of comparable molecular masses. All the reactions and bonding diagrams are given in the PDF.
Q: Why do primary amines have a higher boiling point than tertiary amines?
A: In a molecule of a tertiary amine, there are no H-atoms. Whereas in the primary amines, two hydrogen atoms are present. Due to the presence of H-atoms, primary amines undergo extensive intermolecular H-bonding.
Very less hydrogen bonding in tertiary amine due to steric hindrance of the alkyl group (-R). To break the hydrogen bond, extra energy is required to separate the molecules of primary amines. Hence, primary amines have higher boiling points than tertiary amines. For reactions and diagrams, download the PDF given below.
If you are satisfied with the solutions provided above, then click on the direct link provided below and download all the NCERT Solutions For Class 12 Chemistry Chapter 6 in PDF.
FAQs Related to NCERT Solutions for Class 12 Chemistry Chapter 13 PDF Download
A. You can download the CBSE NCERT Class 12 Chemistry Chapter 13 solutions for Amines from Embibe.
A. You can solve CBSE Class 12 Chemistry Chapter 13 questions for free on Embibe.
A. There are a total of 10 exercises in NCERT Solutions for Class 12 Chemistry Chapter 10 PDF Download:
Ex. 13.1: Structure of Amines
Ex. 13.2: Classification
Ex. 13.3: Nomenclature
Ex. 13.4: Preparation of Amines
Ex. 13.5: Physical Properties
Ex. 13.6: Chemical Reactions
Ex. 13.7: Method of Preparation of Diazonium Salts
Ex. 13.8: Physical Properties
Ex. 13.9: Chemical Reactions
Ex. 13.10: Importance of Diazonium Salts in the Synthesis of Aromatic Compounds
A. You can best prepare a primary amine from its alkylazide by reduction or by the Gabriel synthesis. In the Gabriel synthesis, potassium phthalimide is reacted with an alkyl halide to produce an N‐alkyl phthalimide. Then, aqueous acids or bases can hydrolyze this N‐alkyl phthalimide into the primary amine.
A. Diazonium salts are named by suffixing diazonium to the name of the parent hydrocarbon from which they are formed, followed by the name of anion such as chloride, hydrogensulphate, etc. The N2+ group is called diazonium salt.
Amines are an important concept considered in the whole Organic Chemistry. By downloading this PDF, you can get in touch with one of the best strategies to solve its NCERT questions. Also, Class 12 Chemistry has a lot of importance in engineering and medical examinations. Therefore, keeping these solutions handy will surely help you.
|NCERT Solutions for Class 12 Chemistry Chapter 12||Class 12 NCERT Solution For All Chapters of Chemistry||Class 12 NCERT Solutions For Chemistry Chapter 14|
To enhance your preparation, we have the best free CBSE Class 12th Chapter 13 Questions. This will assist you in preparing for your entrance examinations a lot better. Analyzing these mocks will help you know your weak areas, which you can work on.
Now that you have all the necessary NCERT Solutions For Class 12 Chemistry Chapter 13, we hope it helps you.
If you have any queries, do let us know about them in the comment section below. We will surely help you out soon.557 Views