Trigonometric function is one of the most important topics taught in class 9th, which will be useful throughout life. Trigonometric functions are formed when trigonometric ratios are studied in terms of radian measure for any angle (0, 30, 90, 180, 270..). These are also defined in terms of sine and cosine functions. Students need to have basic knowledge of triangles and their angles to understand trigonometric ratios clearly.

In this article, students will find all the details on trigonometric functions such as value in degree, radians, complete trigonometric table and other relevant information. Students need to follow this article to develop basic knowledge of trigonometry and trigonometric functions.

Embibe offers a range of study materials that include sample test papers, mock tests, PDF of NCERT books and previous year question papers. Students can practice from these study materials for. It will expose them to more number of questions and will further strengthen their ability to perform in the boards.

Trigonometric Functions: Class 11

Here, students will learn how trigonometric functions like sin, cos, tan, cosec, sec, cot are calculated at different values of θ.

Let us take a circle with the centre at the origin of the x-axis. Let P (a, b) be any point on the circle with angle AOP = x radian, i.e., AP = x.

Here cos x = a and sin x = b. Since ∆OMP is a right triangle, we have OM² + MP² = OP² or a² + b² = 1.

So, for every point on circle, we have a² + b² = 1 or cos² x + sin² x = 1. Since a complete revolution creates an angle of 2π radian = 360°, we have ∠AOB = π/2, ∠AOC = π and ∠AOD = 3π/2. Angles that are multiples of π/2 are called quadrantal angles.

The coordinates of the points A, B, C and D are already provided in the figure. Hence, for quadrantal angles, we have the following:

cos 0° = 1	sin 0° = 0
cos π/2 = 0	sin π/2 = 1
cos π = − 1	sin π = 0
cos 3π/2 = 0	sin 3π/2 = –1
cos 2π = 1	sin 2π = 0

Important Note: Sin x = 0 for x = nπ, where n is any integer. Cos x = 0 for x = (2n + 1) π 2 , where n is any integer.

Six Trigonometric Functions

Now that you are aware of how the value of sin and cos at different angles is calculated. Let us now introduce you to other functions like tan, cosec, sec, and cot.

For this, we will require a right-angled triangle.

Sine Function or Sin Function

Sin or sine function is expressed as the ratio of perpendicular to hypotenuse i.e sin θ = a/h.

Cosine Function or Cos Function

Cos or cosine is written as the ratio of Base to hypotenuse i.e cos θ = b/h.

Tangent Function or Tan Function

Tan or tangent function in trigonometry is expressed as the ratio of perpendicular to base i.e tan θ = a/b.

Cosecant Function or Cosec Function

Cosec or cosecant function is the inverse of sin function as has the inverse value of sine i.e cosec θ = h/a.

Secant Function or Sec Function

Sec or secant is the inverse of cos and has the inverse value of cosine function i.e sec θ = h/b.

Cotangent Function or Cot Function

Cot or Cotangent is the inverse of tan function and can also be expressed as cos/sin i.e cot θ = b/a.

Trigonometric Functions Table

We can define other trigonometric functions in terms of sin and cos.

• cosec x = 1/sin x or \(\frac{1}{sin\,x}\), x ≠ nπ, where n is any integer.
• sec x = 1/cos x or \(\frac{1}{cos\,x}\), x ≠ (2n + 1) π 2 , where n is any integer.
• tan x = sin x/cos x or \(\frac{sin\,x}{cos\,x}\), x ≠ (2n +1) π 2 , where n is any integer.
• cot x = cos x/sin x or \(\frac{cos\,x}{sin\,x}\), x ≠ n π, where n is any integer.

Angles	0°	30° or π/6	45° or π/4	60° or π/3	90° or π/2	180° or π	270° or 3π/2	360° or 2π
Sin	0	1/2	1/√2	√3/2	1	0	−1	0
Cos	1	√3/2	1/√2	1/2	0	−1	0	1
Tan	0	1/√3	1	√3	Not Defined	0	Not Defined	0
Cot	Not Defined	√3	1	1/√3	0	Not Defined	0	Not Defined
Cosec	Not Defined	2	√2	2/√3	1	Not Defined	−1	Not Defined
Sec	1	2/√3	√2	2	Not Defined	−1	Not Defined	1

Sign of Trigonometric Functions

Let P (a, b) be a point on a circle with a centre at the origin such that ∠AOP = x. If ∠AOQ = – x, then the coordinates of the point Q will be (a, –b).

So, cos (– x) = cos x and sin (– x) = – sin x

In the same way, we can define other functions as well. Below we have provided the table for the negative or positive value of functions in all four quadrants.

Functions (↓) And Quadrants (→)	I	II	III	IV
Sin x	+	+	–	–
Cos x	+	–	–	+
Tan x	+	–	+	–
Cosec x	+	+	–	–
Sec x	+	–	–	+
Cot x	+	–	+	–

Sine, Cosine, Tangent Graphs

There might be instances where a question involves drawing the graph for the trigonometric function. You can use the table below to draw the graphs.

Function	Definition	Domain	Range
Sine Function	y=sin x	x ∈ R	− 1 ≤ sin x ≤ 1
Cosine Function	y = cos x	x ∈ R	− 1 ≤ cos x ≤ 1
Tangent Function	y = tan x	x ∈ R , x≠(2k+1)π/2,	− ∞ < tan x < ∞
Cotangent Function	y = cot x	x ∈ R , x ≠ k π	− ∞ < cot x < ∞
Secant Function	y = sec x	x ∈ R , x ≠ ( 2 k + 1 ) π / 2	sec x ∈  ( − ∞ , − 1 ] ∪ [ 1 , ∞ )
Cosecant Function	y = csc x	x ∈ R , x ≠ k π	csc x ∈  ( − ∞ , − 1 ] ∪ [ 1 , ∞ )

Functions of Negative Angles

If θ is the angle then we can define all the trigonometric functions as given below:

• (i) sin (– θ) = – sin θ
• (ii) cos (–θ) = cos θ
• (iii) tan (– θ) = – tan θ
• (iv) cot (–θ) = – cot θ sec (–θ) = sec θ
• (v) cosec (– θ) = – cosec θ

Trigonometric Ratios of Complementary Angles

In this section, we have provided you with the complementary angle ratios for all 4 quadrants.

I Quadrant

sin(π/2−\(\theta\)) = \(\cos \theta\) cos(π/2−\(\theta\)) = \(\sin \theta\) tan(π/2−\(\theta\)) = \(\cot \theta\) cot(π/2−\(\theta\)) = \(\tan \theta\) sec(π/2−\(\theta\)) = cosec\(\theta\) cosec(π/2−\(\theta\)) = \(\sec \theta\)

II Quadrant

sin(π−\(\theta\)) = \(\sin \theta\) cos(π−\(\theta\)) = -\(\cos \theta\) tan(π−\(\theta\)) = -\(\tan \theta\) cot(π−\(\theta\)) = -\(\cot \theta\) sec(π−\(\theta\)) = -sec\(\theta\) cosec(π−\(\theta\)) = cosec\(\theta\)

Attempt 10th CBSE Exam Mock Tests

III Quadrant

sin(π+\(\theta\)) = -\(\sin \theta\) cos(π+\(\theta\)) = -\(\cos \theta\) tan(π+\(\theta\)) = \(\tan \theta\) cot(π+\(\theta\)) = \(\cot \theta\) sec(π+\(\theta\)) = -sec\(\theta\) cosec(π+\(\theta\)) = -cosec\(\theta\)

IV Quadrant

sin(2π−\(\theta\)) = -\(\sin \theta\) cos(2π−\(\theta\)) = \(\cos \theta\) tan(2π−\(\theta\)) = -\(\tan \theta\) cot(2π−\(\theta\)) = -\(\cot \theta\) sec(2π−\(\theta\)) = sec\(\theta\) cosec(2π−\(\theta\)) = -cosec\(\theta\)

Trigonometric Functions Formulas

Here are all the formulas related to trigonometric functions that will aid you in your preparation.

• (i) sin (A + B) = sin A cos B + cos A sin B
• (ii) sin (A – B) = sin A cos B – cos A sin B
• (iii) cos (A + B) = cos A cos B – sin A sin B
• (iv) cos (A – B) = cos A cos B + sin A sin B
• (v) Sin 2A = 2 Sin A Cos A
• (vi) Cos 2A = Cos² A – Sin² A = 1 – 2 Sin² A = 2 Cos² A – 1
• (vii) Cos 3A = 4Cos³ A – 3Cos A
• (viii) 2Sin A Cos B = Sin (A + B) + Sin (A – B)
• (ix) 2Cos A Sin B = Sin (A + B) – Sin (A – B)
• (x) 2Cos A Cos B = Cos (A + B) + Cos (A – B)
• (xi) 2Sin A Sin B = Cos (A – B) – Cos (A + B)
• (xii) Tan (A + B) = (Tan A + Tan B) ÷ (1 − Tan A tan B)
• (xiii) Tan (A – B) = (Tan A − Tan B) ÷ (1 + Tan A Tan B)
• (xiv) Tan 2A = (2 Tan A) ÷ (1 – Tan² A)
• (xv) Tan 3A = (3 Tan A – Tan³ A) ÷ (1 – 3Tan² A)
• (xvi) Cot (A + B) = (Cot A Cot B − 1) ÷ (Cot A + Cot B) 
• (xvii) Cot (A − B) = (Cot A Cot B + 1) ÷ (Cot B − Cot A) 

Trigonometric Equations

Equations that involve trigonometric functions of a variable are called trigonometric equations. The solutions of a trigonometric equation for which 0 ≤ x < 2π are called principal solutions.

The expression involving integer ‘n’ which gives all solutions of a trigonometric equation is called the general solution. The best way to explain this topic is via examples.

Example 1: Find the principal solutions of the equation sin x = 3/2.

Solution: From the trigonometric table we know that, sin π/3 = √3/2 and sin 2π/3 = sin (π − π/3) = sin (π/3) = √3/2.

Therefore, principal solutions are x = π/3 and 2π/3.

Sample Questions on Basic Trigonometric Functions

You can solve the below questions using the concepts explained on this page to improve your preparation and score better marks:

Question 1: Find the principal solutions of the equation tan x = −1/√3.

Question 2: Find the solution of sin x = – √3/2.

Question 3: Solve cos x = 1/2.

Question 4: Solve tan 2x = − cot (x + π/3).

Question 5: Solve sin 2x – sin 4x + sin 6x = 0.

Question 6: Solve 2 cos2 x + 3 sin x = 0.

Question 7: Find the general solution of sin x + sin 3x + sin 5x = 0.

Question 8: Find the value of tan π/8.

Question 9: Prove that (sin 3x + sin x) sin x + (cos 3x – cos x) cos x = 0.

Question 10: (cos x + cos y)2 + (sin x – sin y)2 = 4 cos2 ((x + y)/2).

Study on Embibe

Students can access the following study materials on Embibe for their exam preparation:

NCERT Solutions	NCERT Books
Class 8 Mock Test Series	Class 8 Practice Questions
Class 9 Mock Test Series	Class 9 Practice Questions
Class 10 Mock Test Series	Class 10 Practice Questions
JEE Main Mock Tests  (Class 11-12 PCM)	JEE Main Practice Questions  (Class 11-12 PCM)
NEET Mock Tests  (Class 11-12 PCB)	NEET Practice Questions  (Class 11-12 PCB)

FAQs On Trigonometric Functions

Now let us have a look at the questions that are mostly searched on the topic:

Q. What are the 9 trigonometrical identities? Ans. Not just 9 we have provided more than 20 trig identities on this page that will help you in solving the questions.

Q. What are the six basic trigonometric functions? Ans. The basic trigonometric functions are sine or sin, cosine or cos, tangent or tan, secant or sec, cosecant or cosec, cotangent or cot.

Q. How do you find the 6 trigonometric functions? Ans. We have provided a detailed explanation to find all the 6 trigonometric functions on this page.

Q. What is the use of trigonometric functions? Ans. These functions are used to find the angles or sides of a triangle. These have real-life applications as well.

So after providing you with all the useful information on trigonometric functions we have reached the end of this article. If you have further questions feel to use the comments section and we will get back to you at the earliest.