At the very outset, let us give you a little insight about the term vedic; the term vedic comes from the word vid. Vid means limitless. You might have heard your parents or grand parents mentioning vedas and puranas. These are some scriptures, instead very scientific and intelligent scriputres which covers larger topics of humanity, knowledge and deep insight of almost everything.
So here’s the thing; while the eastern hemisphere currently is busy negotiating and struggling with neo pseudo issues, the western world is involving themselves in more logical and required streams of science and philosophy. However, this scene was greatly the exact opposite in 1015 AD’s. That time, the western world was busy squabbling over religious, fanaticism, wars and superstition and the Eastern world was busy with education, science, mathematics, astronomy, astrophysics, and philosophy.
You, might have heard people saying no one can actually really beat Indians in mathematics. Most of you are cynical about this testimony. What if I tell you, this is actually true?
You might have also heard that we as Indians cannot master the English language, but again Why and how?
The answer is simple; it’s not our language and hence we collectively cannot master it. The same philosophy is applied when we have to answer the question that why can no one beat India in Mathematics. We don’t literally own Maths, but quiet logically and functionally we are the creators of sorts for mathematics. Same ideology can be applied to chess. Chess is an Indian game and for far long now and Indian has been dominating it with a few exception here and there, but that’s an anomaly.
So let’s speak about Vedic Maths and how is it helpful and what makes it so great. For a lot of you Maths was a favorite subject till your 10th standard and you have lost all faith once you enter your 12th class or further then. Others have found it difficult and complicated since forever. We don’t blame you, it’s definitely tricky, but it can become as easy if you learn it in a proper way. We will give you a few tricks on how you can make your life easy with mathematics further in the blog, but till then stay with us.
Why Vedic Maths?
 Vedic maths provide one line, super fast mental methods along with strong cross checking mechanisms
 It is easy, simple and fun to play with
 Brings in new approach and uses pattern recognition; and the best part is it still can be improvised through creativity

In this system, for any problem, there is always one general technique
applicable to all cases and also a number of special pattern problems. The element of choice and flexibility at each stage keeps the mind lively and alert to develop clarity of thought and intuition, and thereby a holistic development of the human brain automatically takes place.  It has some inbuilt potential to get rid of your anxiety issues while you are facing psychological issues around mathematics
What does Vedic Maths Include
So, Vedic maths was pioneered by Swami Bharati Krishna Tirtha and he has in his work identified different sutras i.e formulas. Sutras further contain subsutras and they go like this:
Sutras
Subsutras
It is not confined to only these, but these are the ones which would most likely come handy.
Tricks from Vedic Maths
1. Square of numbers ending wit 5
2. Vulgar fractions whose denominators are numbers ending in 9
There are two ways of doing it.
Value of 1 / 19.
The numbers of decimal places before repetition is the difference of numerator
and denominator, i.e.,, 19 1=18 places.
For the denominator 19, the purva (previous) is 1.
Hence Ekadhikena purva (one more than the previous) is 1 + 1 = 2.
The sutra is applied in a different context. Now the method of division is as
follows:
Step. 1 : Divide numerator 1 by 20.
i.e.,, 1 / 20 = 0.1 / 2 = .10 ( 0 times, 1 remainder)
Step. 2 : Divide 10 by 2
i.e.,, 0.005( 5 times, 0 remainder )
Step. 3 : Divide 5 by 2
i.e.,, 0.0512 ( 2 times, 1 remainder )
Step. 4 : Divide 12 i.e.,, 12 by 2
i.e.,, 0.0526 ( 6 times, No remainder )
Step. 5 : Divide 6 by 2
i.e.,, 0.05263 ( 3 times, No remainder )
Step. 6 : Divide 3 by 2
i.e.,, 0.0526311(1 time, 1 remainder )
Step. 7 : Divide 11 i.e.,, 11 by 2
i.e.,, 0.05263115 (5 times, 1 remainder )
Step. 8 : Divide 15 i.e.,, 15 by 2
i.e.,, 0.052631517 ( 7 times, 1 remainder )
Step. 9 : Divide 17 i.e.,, 17 by 2
i.e.,, 0.05263157 18 (8 times, 1 remainder )
Step. 10 : Divide 18 i.e.,, 18 by 2
i.e.,, 0.0526315789 (9 times, No remainder )
Step. 11 : Divide 9 by 2
i.e.,, 0.0526315789 14 (4 times, 1 remainder )
Step. 12 : Divide 14 i.e.,, 14 by 2
i.e.,, 0.052631578947 ( 7 times, No remainder )
Step. 13 : Divide 7 by 2
11
i.e.,, 0.05263157894713 ( 3 times, 1 remainder )
Step. 14 : Divide 13 i.e.,, 13 by 2
i.e.,, 0.052631578947316 ( 6 times, 1 remainder )
Step. 15 : Divide 16 i.e.,, 16 by 2
i.e.,, 0.052631578947368 (8 times, No remainder )
Step. 16 : Divide 8 by 2
i.e.,, 0.0526315789473684 ( 4 times, No remainder )
Step. 17 : Divide 4 by 2
i.e.,, 0.05263157894736842 ( 2 times, No remainder )
Step. 18 : Divide 2 by 2
i.e.,, 0.052631578947368421 ( 1 time, No remainder )
Now from step 19, i.e.,, dividing 1 by 2, Step 2 to Step. 18 repeats thus giving
0 __________________ . .
1 / 19 =0.052631578947368421 or 0.052631578947368421
Note that we have completed the process of division only by using ‘2’. Nowhere
the division by 19 occurs.
Value of 1 / 19
First we recognize the last digit of the denominator of the type 1 / a9. Here the
last digit is 9.
For a fraction of the form in whose denominator 9 is the last digit, we take the
case of 1 / 19 as follows:
For 1 / 19, ‘previous’ of 19 is 1. And one more than of it is 1 + 1 = 2.
Therefore 2 is the multiplier for the conversion. We write the last digit in the
numerator as 1 and follow the steps leftwards.
Step. 1 : 1
Step. 2 : 21(multiply 1 by 2, put to left)
Step. 3 : 421(multiply 2 by 2, put to left)
Step. 4 : 8421(multiply 4 by 2, put to left)
Step. 5 : 168421 (multiply 8 by 2 =16, 1 carried over, 6 put to left)
Step. 6 : 1368421 ( 6 X 2 =12,+1 [carry over]
= 13, 1 carried over, 3 put to left )
Step. 7 : 7368421 ( 3 X 2, = 6 +1 [Carryover]
= 7, put to left)
Step. 8 : 147368421 (as in the same process)
Step. 9 : 947368421 ( Do – continue to step 18)
Step. 10 : 18947368421
Step. 11 : 178947368421
Step. 12 : 1578947368421
Step. 13 : 11578947368421
Step. 14 : 31578947368421
Step. 15 : 631578947368421
Step. 16 : 12631578947368421
Step. 17 : 52631578947368421
Step. 18 : 1052631578947368421
Now from step 18 onwards the same numbers and order towards left continue.
Thus 1 / 19 = 0.052631578947368421
3. Urdhva – tiryagbhyam
(a) Multiplication of two 2 digit numbers.
Ex.1: Find the product 14 X 12
i) The right hand most digit of the multiplicand, the first number (14) i.e.,4 is
multiplied by the right hand most digit of the multiplier, the second number
(12)i.e., 2. The product 4 X 2 = 8 forms the right hand most part of the answer.
ii) Now, diagonally multiply the first digit of the multiplicand (14) i.e., 4 and
second digit of the multiplier (12)i.e., 1 (answer 4 X 1=4); then multiply the
second digit of the multiplicand i.e.,1 and first digit of the multiplier i.e., 2
(answer 1 X 2 = 2); add these two i.e.,4 + 2 = 6. It gives the next, i.e., second
digit of the answer. Hence second digit of the answer is 6.
&nsbp;
iii) Now, multiply the second digit of the multiplicand i.e., 1 and second digit of
the multiplieri.e., 1 vertically, i.e., 1 X 1 = 1. It gives the left hand most part of
the answer.
Thus the answer is 16 8.
4. Paravartya Yojayet
‘Paravartya – Yojayet’ means ‘transpose and apply’
(i) Consider the division by divisors of more than one digit, and when the
divisors are slightly greater than powers of 10.
Example 1 : Divide 1225 by 12.
Step 1 : (From left to right ) write the Divisor leaving the first digit, write the
other digit or digits using negative () sign and place them below the divisor
as shown.
12
2
????
Step 2 : Write down the dividend to the right. Set apart the last digit for the
remainder.
42
i.e.,, 12 122 5
– 2
Step 3 : Write the 1st digit below the horizontal line drawn under
thedividend. Multiply the digit by –2, write the product below the 2nd digit
and add.
i.e.,, 12 122 5
2 2
????? ????
10
Since 1 x –2 = 2and 2 + (2) = 0
Step 4 : We get second digits’ sum as ‘0’. Multiply the second digits’ sum
thus obtained by –2 and writes the product under 3rd digit and add.
12 122 5
– 2 20
???? ??????????
102 5
Step 5 : Continue the process to the last digit.
i.e., 12 122 5
– 2 20 4
????? ??????????
102 1
Step 6: The sum of the last digit is the Remainder and the result to its left is
Quotient.
Thus Q = 102 andR = 1
Example 2 : Divide 1697 by 14.
14 1 6 9 7
– 4 4–8–4
???? ???????
1 2 1 3
Q = 121, R = 3
Example 4 : Divide 239479 by 11213. The divisor has 5 digits. So the last
4digits of the dividend are to be set up for Remainder.
1 1213 2 3 9 4 7 9
1213 2 426 with 2
???????? 1213 with 1
?????????????
2 1 40 0 6
Hence Q = 21, R = 4006.