NCERT Solutions for Class 6 Maths Chapter 8 Decimals - Embibe
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• Written By Khushbu

# NCERT Solutions for Class 6 Maths Chapter 8: Get PDFs NCERT Solutions for Class 6 Maths Chapter 8: Students from all over India who are using NCERT textbooks for their Class 6 Maths exam preparation, can refer to the solutions provided here. These are provided by the top Maths experts at Embibe. With the help of these NCERT solutions for Class 6 Maths Chapter 8, students will be able to understand the concepts better and complete their assignments and homework on time.

The solutions provided here are prepared by the top academic experts at Embibe as per the NCERT Maths textbook. You can download the complete solution for free in PDF format to study offline. We have provided the students with the exercise-wise solutions to help the students prepare well for the exam. Keep reading the article to access the NCERT solutions for chapter 8 of Class 6 Maths.

## Class 6 Maths Chapter 8 Solution Decimals: Overview

Before getting into the detailed solutions, let’s have a look at the different topics and subtopics in this chapter:

### NCERT Solutions for Class 6 Maths Chapter 8: Decimals PDF Download

Here we have provided the solutions for chapter 8 of NCERT books for Class 6 Maths. The chapter-wise solutions provided in this article will help the students build fundamentals of the Decimals concepts and make them proficient in calculating complicated problems related to Decimals in the future.

Also, the solutions have been explained in a step-wise manner to help students decode and understand the solutions easily.

Question: Write the following as decimal:
Let us consider an example:
: Let us consider an example:
Two hundred and nine ones
To convert into numeral form, we will get a number in decimal.
Two hundred and nine ones=209
One hundred and two ones =(1×100)+(2×1)
=100+2 =102 Hence, the required decimal form is 102.

Question: Write the following as decimal:
Six hundred point eight
: We need to write six hundred point eight as a decimal.
Let us consider an example:
Sixteen point eight. To convert into numeral form, we will get a number in decimal. Sixteen point eight=16.8. Six hundred point eight =6×100+0.8=600.8. Hence, the required decimal form is 600.8.

Download NCERT Solutions for Class 6 Maths Chapter 8 PDF

### Download NCERT Solutions for Class 6 Maths for Other Chapters

Students can find the free NCERT solutions for all the chapters of Class 6 Maths below.

### CBSE Class 6 Maths Chapter 8 Decimals: Chapter Summary

In NCERT Class 6 Maths Chapter 8, you will read about the Decimals. This chapter deals with the concept of representing decimals on a number line. Students will learn to represent the decimal numbers on the number line in detail.

This chapter explains tenths, and hundredths and compares decimals. After this, the concept of “Addition of Numbers with Decimals” and “Subtraction of Decimals” are dealt with. By the end of this chapter, you will be able to explain the representing units of Money, Length, and Weight.

### FAQs on NCERT Maths Solution Class 6 Chapter 8

Q.1: Write each of the following as decimals:
(a) Seven-tenths
(b) Two tens and nine-tenths
(c) Fourteen point six
(d) One hundred and two ones
(e) Six hundred point eight

Ans: (a) The decimal form of Seven-tenths is 7 / 10 = 0.7
(b) The decimal form of two tens and nine tenths is 20 + 9 / 10 = 20.9
(c) The decimal form of fourteen point six is 14.6
(d) The decimal form of one hundred and two ones is 100 + 2 = 102.0
(e) The decimal form of six hundred points eight is 600.8

Q.2: Write each of the following as decimals:
(a) 5 / 10
(b) 3 + 7 / 10
(c) 200 + 60 + 5 + 1 / 10
(d) 70 + 8 / 10
(e) 88 / 10

Ans: (a) 5 / 10 = 0.5
(b) 3 + 7 / 10 = 3 + 0.7
= 3.7
(c) 200 + 60 + 5 + 1 / 10 = 265 + 0.1
= 265.1
(d) 70 + 8 / 10 = 70 + 0.8
= 70.8
(e) 88 / 10 = 80 / 10 + 8 / 10
= 8 + 0.8
= 8.8

Q.3: Write the following decimals as fractions. Reduce the fraction to the lowest form.
(a) 0.6
(b) 2.5
(c) 1.0
(d) 3.8
(e) 13.7
(f) 21.2
(g) 6.4

Ans: (a) 0.6 = 6 / 10
= 3 / 5
(b) 2.5 = 25 / 10
= 5 / 2
(c) 1.0 = 1
= 1
(d) 3.8 = 38 / 10
= 19 / 5
(e) 13. 7 = 137 / 10
(f) 21.2 = 212 / 10
= 106 / 5
(g) 6.4 = 64 / 10
= 32 / 5

Q.4: Between which two whole numbers on the number line are the given numbers lie?
Which of these whole numbers is nearer the number?

(a) 0.8
(b) 5.1
(c) 2.6
(d) 6.4
(e) 9.1
(f) 4.9
Ans: (a) 0.8 lies between 0 and 1
0.8 is nearer to 1
(b) 5.1 lies between 5 and 6
5.1 is nearer to 5
(c) 2.6 lies between 2 and 3
2.6 is nearer to 3
(d) 6.4 lies between 6 and 7
6.4 is nearer to 6
(e) 9.1 lies between 9 and 10
9.1 is nearer to 9
(f) 4.9 lies between 4 and 5
4.9 is nearer to 5

Q.5: Write the following decimals in the place value table.
(a) 0.29
(b) 2.08
(c) 19.60
(d) 148.32
(e) 200.812

Ans: (a) 0.29
= 0.2 + 0.09
= 2 / 10 + 9 / 100
(b) 2.08
= 2 + 0.08
= 2 + 8 / 100
(c) 19.60
= 19 + 0.60
= 10 + 9 + 6 / 10
(d) 148.32
= 148 + 0.3 + 0.02
= 100 + 40 + 8 + 3 / 10 + 2 / 100
(e) 200.812
= 200 + 0.8 + 0.01 + 0.002
=200 + 8 / 10 + 1 / 100 + 2 / 1000

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