NCERT Solutions for Class 8 Maths Chapter 12: The first step towards your preparation for tests and exams will be solving the NCERT exercise questions. Every time you finish a chapter, you need to solve the questions at the end of it. Students of Class 8 who are looking for NCERT Solutions for Class 8 Chapter 12 Maths can refer to this article where experts at Embibe have provided detailed solutions for all intext and exercise questions from this chapter.
The solutions provided here are accurate and simple to follow. This will help you as a guide to answer the NCERT exercise questions and to complete your homework or assignments on time. Besides, the NCERT Solutions for Class 8 Maths provided here will also be handy for practice and revision during your exam preparation.
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Table of Contents
NCERT Solutions For Class 8 Maths Chapter 12: Exponents And Powers
Before we provide you with Class 8 NCERT Solutions Maths Chapter 12, let’s have an overview of the topics in this chapter. Click on any topic to download the solutions as a PDF.
| Exercise | Topics |
| 12.1 | Powers With Negative Exponents |
| 12.2 | Laws of Exponents |
| 12.3 | Use of Exponents to Express Small Numbers in Standard Form |
Also, Check:
NCERT Solutions For Class 8 Maths Chapter 12: Solved Exercises And In-Text Questions
Students can check Class 8 NCERT Solutions for Maths for each exercise and in-text questions on this page. Also, we have provided NCERT Class 8 Maths Chapter 12 PDF download link below these solutions:
Download CBSE CLASS 8 MATHS CHAPTER 12 SOLUTIONS PDF NOW
Download CBSE Class 8 Solutions for Maths for other chapters from the table below:
- Chapter 1 – Rational Numbers
- Chapter 2 – Linear Equations in One Variable
- Chapter 3 – Understanding Quadrilaterals
- Chapter 4 – Practical Geometry
- Chapter 5 – Data Handling
- Chapter 6 – Squares and Square Roots
- Chapter 7 – Cubes and Cube Roots
- Chapter 8 – Comparing Quantities
- Chapter 9 – Algebraic Expressions and Identities
- Chapter 10 – Visualizing Solid Shapes
- Chapter 11 – Mensuration
- Chapter 13 – Direct and Inverse Proportions
- Chapter 14 – Factorization
- Chapter 15 – Introduction to Graphs
- Chapter 16 – Playing with Numbers
NCERT Solutions For Class 8 Maths Chapter 12: Chapter Summary
When we have to repeatedly multiply a number by itself, we raise it to power. This is known as the Exponent. The power in the exponent represents the number of times that we want to carry out the multiplication operation. Exponents have their own set of rules when it comes to carrying out arithmetic operations. In this chapter, we will learn about powers, exponents, and their peripheral rules. Students will get to learn about new concepts and this chapter will further strengthen their base of the concepts of exponents and powers.
How To Prepare For CBSE Class 8 Maths Exponents And Powers?
Students are advised that they develop a good understanding of the concepts discussed in this chapter. Make sure you utilize these solutions provided here in the best possible way. Solving the Exponents and Powers practice questions will help you know where you are standing and will also help you to cover the areas you are weak at. If you are not able to answer a question or get stuck somewhere, refer to the solutions provided here. Also, go back and learn the concepts related to it. You can also take CBSE Class 8 Maths Chapter 12 mock test on Embibe. It is available for free and will be of great help to you in your preparation.
CBSE Class 8 Maths Chapter 12 Important Questions
| Important Questions From Exponents And Powers |
- Simplify the following expression and express the result in positive power notation: (−4)5 ÷ (−4)8
- 3 multiplied for 15 times is written as?
- Find the value of (40 + 4-1) × 22
- Solve 3-4 and (½)-2
- Express 4-3 as a power with base 2.
- Calculate the missing value of “x” in the following expression: (11/9)3 × (9/11)6 = (11/9)2x-1
- 5 books and 5 paper sheets are placed in a stack. Find the total thickness of the stack if each book has a thickness of 20 mm and each sheet has a thickness of 0.016 mm.
- Simplify [25 x t-4]/[5-3 x 10 x t-8]
- If a new-born bear weighs 4kg, calculate how many kilograms a five-year-old bear weigh if its weight increases by the power of 2 in 5 years?
- Write 3.61492 x 106 in the usual form.
- Express 0.00000000837 in standard form.
- Evaluate: [{1/2}-1+{1/3}-1]-1
- Express 31860000000 in standard form.
- Evaluate: (-4)-3
- A dish holds 100 bacteria. It is known that the bacteria double in number every hour. How many bacteria will be present after each number of hours?
- Express the following large numbers in its scientific notation.
(a) 650200000000
(b) 301000000 - Express the following number as a product of powers of prime factors.
(a) 1225
(b) 3600
FAQs Related To CBSE Class 8 Maths Chapter 1 Solutions
Here we have provided some of the frequently asked questions related to this chapter:
(i) 3.02×10-6
(ii) 4.5×104
(iii)3×10-8
(iv)1.0001×109
(v) 5.8×1012
(vi)3.61492×106
A: (i) 3.02×10-6 = 3.02/106 = 0 .00000302
(ii) 4.5×104 = 4.5×10000 = 45000
(iii) 3×10-8 = 3/108 = 0.00000003
(iv) 1.0001×109 = 1000100000
(v) 5.8×1012 = 5.8×1000000000000 = 5800000000000
(vi) 3.61492×106 = 3.61492×1000000 = 3614920
A: Thickness of one book = 20 mm
Thickness of 5 books = 20×5 = 100 mm
Thickness of one paper = 0.016 mm
Thickness of 5 papers = 0.016×5 = 0.08 mm
Total thickness of a stack = 100+0.08 = 100.08 mm
= 100.08×102/102 mm
= 1.0008×102 mm
(i) 1 micron is equal to 1/1000000 m.
(ii) Charge of an electron is 0.000, 000, 000, 000, 000, 000, 16 coulomb.
(iii) Size of bacteria is 0.0000005 m
(iv) Size of a plant cell is 0.00001275 m
(v) Thickness of a thick paper is 0.07 mm
A: (i) 1 micron = 1/1000000
= 1/106
= 1×10-6
(ii) Charge of an electron is 0.00000000000000000016 coulombs.
= 0.00000000000000000016×1019/1019
= 1.6×10-19 coulomb
(iii) Size of bacteria = 0.0000005
= 5/10000000 = 5/107 = 5×10-7 m
(iv) Size of a plant cell is 0.00001275 m
= 0.00001275×105/105
= 1.275×10-5m
(v) Thickness of a thick paper = 0.07 mm
0.07 mm = 7/100 mm = 7/102 = 7×10-2 mm
A: 5m ÷ 5-3 = 55
5(m-(-3) ) = 55
5m+3 = 55
Comparing exponents both sides, we get
m+3 = 5
m = 5-3
m = 2
(i) 3-2 (ii) (-4)-2 (iii) (1/2)-5
A: (i) 3-2 = (1/3)2
= 1/9
(ii) (-4)-2 = (1/-4)2
= 1/16
(iii) (1/2)-5 = (2/1)5
= 25
= 32
Practice Questions From Exponents & Powers Now
You can solve the free CBSE Class 8 practice questions on Embibe for Mathematics and Science. You can also take CBSE Class 8 Mock Tests for these subjects. These will be of great help to you.
If you have any query regarding this article on Class 8th Maths Chapter 12, kindly drop your questions in the comment box below and we will get back to you as soon as possible. Stay tuned to Embibe for the latest updates.
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