**NCERT Solutions For Class 8 Maths Chapter 9: **The solutions for** Algebraic Expressions and Identities **will help all Class 8 students in their homework. Also, these **NCERT Solutions** will be very helpful during the final exam preparation. All the questions are solved considering the latest CBSE guidelines so that students can score maximum marks in the exam.

Students can also download these solutions as a PDF to study in offline mode. With the help of these **Class 8 Maths Solutions** for Chapter 9, students will learn about different algebraic expressions and identities formulas. All these solutions are prepared by top academic experts at Embibe. Moreover, these solutions have been written in an easy-to-understand manner so that any 8th class student can understand it.

**Solve Important Questions On Class 8 Algebra**

**NCERT Solutions For Class 8 Maths Chapter 9 PDF**

Before getting into the details of **CBSE Class 8 Solutions** for Maths Chapter 9, let’s have an overview of topics and sub-topics covered in this chapter – Algebraic Expressions and Identities. Click on any topic to download its solutions as a PDF.

9.1 | What are Expressions? | 9.8 | Multiplying a Monomial by a Polynomial |

9.2 | Terms, Factors and Coefficients | 9.8.1 | Multiplying a monomial by a binomial |

9.3 | Monomials, Binomials and Polynomials | 9.8.2 | Multiplying a monomial by a trinomial |

9.4 | Like and Unlike Terms | 9.9 | Multiplying a Polynomial by a Polynomial |

9.5 | Addition and Subtraction of Algebraic Expressions | 9.9.1 | Multiplying a binomial by a binomial |

9.6 | Multiplication of Algebraic Expressions: Introduction | 9.9.2 | Multiplying a binomial by a trinomial |

9.7 | Multiplying a Monomial by a Monomial | 9.10 | What is Identity? |

9.7.1 | Multiplying two monomials | 9.11 | Standard Identities |

9.7.2 | Multiplying three or more monomials | 9.12 | Applying Identities |

**Also check,**

### Class 8 Maths Chapter 9: Algebraic Expressions And Identities Summary

Algebraic Expressions are the expressions formed from variables and constants.

In this chapter, students will learn about topics such as: What are Expressions? Terms, Factors and Coefficients, Monomials, Binomials and Polynomials, Like and Unlike Terms, Addition and Subtraction of Algebraic Expressions, Multiplication of Algebraic Expressions: Introduction, Multiplying a Monomial by a Monomial, Multiplying two monomials, Multiplying three or more monomials, Multiplying a Monomial by a Polynomial, Multiplying a monomial by a binomial, Multiplying a monomial by a trinomial, Multiplying a Polynomial by a Polynomial, Multiplying a binomial by a binomial, Multiplying a binomial by a trinomial, What is an Identity? Standard Identities and Applying Identities.

### CBSE NCERT Solutions For Class 8 Maths Chapter 9: Solved Exercises And In-Text Questions

Students can avail the solved exercises for Class 8 Maths Chapter 9 below. Also, you can download these solutions as a PDFto refer to in offline mode as well*.*

**Practice 8th CBSE Exam Questions**

**DOWNLOAD NCERT SOLUTIONS PDF FOR Class 8 Maths Chapter 9**

*Download CBSE Class 8 Solutions for Maths for other chapters from the table below:*

**Chapter 1 – Rational Numbers****Chapter 2 – Linear Equations in One Variable****Chapter 3 – Understanding Quadrilaterals****Chapter 4 – Practical Geometry****Chapter 5 – Data Handling****Chapter 6 – Squares and Square Roots****Chapter 7 – Cubes and Cube Roots****Chapter 8 – Comparing Quantities****Chapter 10 – Visualizing Solid Shapes****Chapter 11 – Mensuration****Chapter 12 – Exponents & Powers****Chapter 13 – Direct and Inverse Proportions****Chapter 14 – Factorization****Chapter 15 – Introduction to Graphs****Chapter 16 – Playing with Numbers**

### FAQs Related To NCERT Solutions For Class 8 Maths Chapter 9

Here we have provided some of the frequently asked questions related to this chapter:

**Q1: Add the following.**

(i) ab – bc, bc – ca, ca – ab

(ii) a – b + ab, b – c + bc, c – a + ac

(iii) 2p2q2 – 3pq + 4, 5 + 7pq – 3p2q2

(iv) l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl

(i) ab – bc, bc – ca, ca – ab

(ii) a – b + ab, b – c + bc, c – a + ac

(iii) 2p2q2 – 3pq + 4, 5 + 7pq – 3p2q2

(iv) l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl

A: **i)** (ab – bc) + (bc – ca) + (ca-ab)

= ab – bc + bc – ca + ca – ab

= ab – ab – bc + bc – ca + ca

= 0**ii)** (a – b + ab) + (b – c + bc) + (c – a + ac)

= a – b + ab + b – c + bc + c – a + ac

= a – a +b – b +c – c + ab + bc + ca

= 0 + 0 + 0 + ab + bc + ca

= ab + bc + ca**iii)** 2p^{2}q* ^{2} – 3pq + 4, 5 + 7pq – 3p^{2}*q

^{2}

= (2p

^{2}q

^{2}– 3pq + 4) + (5 + 7pq – 3p

^{2}q

^{2})

= 2p

^{2}q

^{2}– 3p

^{2}q

^{2}– 3pq + 7pq + 4 + 5

= – p

^{2}q

^{2}+ 4pq + 9

**iv)**(l

^{2}+ m

^{2}) + (m

^{2}+ n

^{2}) + (n

^{2}+ l

^{2}) + (2lm + 2mn + 2nl)

= l

^{2}+ l

^{2}+ m

^{2}+ m

^{2}+ n

^{2}+ n

^{2}+ 2lm + 2mn + 2nl

= 2l

^{2}+ 2m

^{2}+ 2n

^{2}+ 2lm + 2mn + 2nl

**Q2:**

(i) 4, 7p

(ii) – 4p, 7p

(iii) – 4p, 7pq

(iv) 4p

(v) 4p, 0

**Find the product of the following pairs of monomials.**(i) 4, 7p

(ii) – 4p, 7p

(iii) – 4p, 7pq

(iv) 4p

^{3}, – 3p(v) 4p, 0

A: (i) 4 , 7 p = 4 7 × p = 28p

(ii) – 4p × 7p = (-4 × 7 ) × (p × p )= -28p^{2}

(iii) – 4p × 7pq =(-4 × 7 ) (p × pq) = -28p^{2}q

(iv) 4p^{3} × – 3p = (4 × -3 ) (p^{3} × p ) = -12p^{4}

(v) 4p × 0 = 0

**Q3:**

**Obtain the volume of rectangular boxes with the following length, breadth and height respectively.****(i)***5a, 3a*^{2}, 7a^{4}**(ii)***2p, 4q, 8r***(iii)***xy, 2x*^{2}y, 2xy^{2}**(iv)***a, 2b, 3c*A: Volume of rectangle = length x breadth x height. To evaluate the volume of rectangular boxes, multiply all the monomials.*(i) 5a* x *3a*^{2} x *7a*^{4} = (5 × 3 × 7) (a × *a*^{2} × *a*^{4} ) = *105a ^{7}*

*(ii) 2p*x

*4q*x

*8r*= (2 × 4 × 8 ) (p × q × r ) =

*64pqr*

*(iii) y*×

*2x*y ×

^{2}*2xy*

^{2}=(1 × 2 × 2 )( x ×

*x*× x × y × y ×

^{2}*y*

^{2}) =

*4x*y

^{4}^{4}

*(iv) a*x

*2b*x

*3c = (1 × 2 × 3 ) (a × b × c) = 6abc*

**Q4:**

**Identify the terms, their coefficients for each of the following expressions. (i) 5xyz**^{2}– 3zy (ii) 1 + x + x^{2}(iii) 4x^{2}y^{2}– 4x^{2}y^{2}z^{2}+ z^{2}(iv) 3 – pq + qr – p (v) (x/2) + (y/2) – xy (vi) 0.3a – 0.6ab + 0.5bA: The answer is tabulated below:

**Q5:**

**Obtain the product of****(i) xy, yz, zx****(ii) a, – a**^{2}, a^{3}**(iii) 2, 4y, 8y**^{2}, 16y^{3}**(iv) a, 2b, 3c, 6abc****(v) m, – mn, mnp**A: (i) xy × yz × zx = *x ^{2 }*y

*z*

^{2 }

^{2}(ii) a × – a

^{2}× a

^{3 }= – a

^{6}

(iii) 2 × 4y × 8y

^{2}× 16y

^{3 }= 1024 y

^{6}

(iv) a × 2b × 3c × 6abc = 36a

^{2 }b

^{2 }c

^{2}

(v) m × – mn × mnp = –m

^{3 }n

^{2 }p

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