CBSE NCERT Solutions For Class 8 Maths Chapter 9 - Embibe
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• Written By Varsha CBSE NCERT Solutions for Class 8 Maths: The solutions for Algebraic Expressions and Identities will help all Class 8 students in their homework. Also, these CBSE NCERT Solutions for Class 8 Maths will be very helpful during the final exam preparation. All the questions are solved considering the latest CBSE guidelines so that students can score maximum marks in the exam. Students can also download these solutions as a PDF to study in offline mode.

With the help of these CBSE NCERT Solutions for Class 8 Maths for Chapter 9, students will learn about different algebraic expressions and identity formulas. All these solutions are prepared by top academic experts at Embibe. Moreover, these solutions have been written in an easy-to-understand manner so that any 8th class student can understand them.

## CBSE NCERT Solutions for Class 8 Maths Chapter 9 PDF

Before getting into the details for Class 8 Ch 9 Maths Solutions, let us have an overview of the topics and sub-topics covered in this chapter – Algebraic Expressions and Identities. Click on any topic to download its solutions as a PDF.

Also, check:

### Class 8 Maths Chapter 9: Algebraic Expressions And Identities Summary

Algebraic Expressions are the expressions formed from variables and constants.

In this chapter, students will learn about topics such as: What are Expressions? Terms, Factors and Coefficients, Monomials, Binomials and Polynomials, Like and Unlike Terms, Addition and Subtraction of Algebraic Expressions, Multiplication of Algebraic Expressions: Introduction, Multiplying a Monomial by a Monomial, Multiplying two monomials, Multiplying three or more monomials, Multiplying a Monomial by a Polynomial, Multiplying a monomial by a binomial, Multiplying a monomial by a trinomial, Multiplying a Polynomial by a Polynomial, Multiplying a binomial by a binomial, Multiplying a binomial by a trinomial, What is an Identity? Standard Identities and Applying Identities.

### CBSE NCERT Solutions For Class 8 Maths Chapter 9: Solved Exercises And In-Text Questions

Students can avail of the solved exercises for Class 8 Maths Chapter 9 below. Also, you can download these solutions as a PDF to refer to them in offline mode as well.

Practice 8th CBSE Exam Questions

Download CBSE Class 8 Solutions for Maths for other chapters from the table below:

Here we have provided some of the frequently asked questions related to this chapter.

(i) ab – bc, bc – ca, ca – ab
(ii) a – b + ab, b – c + bc, c – a + ac
(iii) 2p2q2 – 3pq + 4, 5 + 7pq – 3p2q2
(iv) l2 + m2, m2 + n2, n2 + l2, 2lm + 2mn + 2nl

A: i) (ab – bc) + (bc – ca) + (ca-ab)
= ab – bc + bc – ca + ca – ab
= ab – ab – bc + bc – ca + ca
= 0
ii) (a – b + ab) + (b – c + bc) + (c – a + ac)
= a – b + ab + b – c + bc + c – a + ac
= a – a +b – b +c – c + ab + bc + ca
= 0 + 0 + 0 + ab + bc + ca
= ab + bc + ca
iii) 2p2q2 – 3pq + 4, 5 + 7pq – 3p2q2
= (2p2q2 – 3pq + 4) + (5 + 7pq – 3p2q2)
= 2p2q2 – 3p2q2 – 3pq + 7pq + 4 + 5
= – p2q2 + 4pq + 9
iv)(l2 + m2) + (m2 + n2) + (n2 + l2) + (2lm + 2mn + 2nl)
= l2 + l2 + m2 + m2 + n2 + n2 + 2lm + 2mn + 2nl
= 2l2 + 2m2 + 2n2 + 2lm + 2mn + 2nl

Q2: Find the product of the following pairs of monomials.
(i) 4, 7p
(ii) – 4p, 7p
(iii) – 4p, 7pq
(iv) 4p3, – 3p
(v) 4p, 0

A: (i) 4 , 7 p = 4 7 × p = 28p
(ii) – 4p × 7p = (-4 × 7 ) × (p × p )= -28p2
(iii) – 4p × 7pq =(-4 × 7 ) (p × pq) = -28p2q
(iv) 4p3 × – 3p = (4 × -3 ) (p3 × p ) = -12p4
(v) 4p × 0 = 0

Q3: Obtain the volume of rectangular boxes with the following length, breadth and height respectively.
(i) 5a, 3a2, 7a4
(ii) 2p, 4q, 8r
(iii) xy, 2x2y, 2xy2
(iv) a, 2b, 3c

A: Volume of rectangle = length x breadth x height. To evaluate the volume of rectangular boxes, multiply all the monomials.
(i) 5a x 3a2 x 7a4 = (5 × 3 × 7) (a × a2 × a4 ) = 105a7
(ii) 2p x 4q x 8r = (2 × 4 × 8 ) (p × q × r ) = 64pqr
(iii) y × 2x2y × 2xy2 =(1 × 2 × 2 )( x × x2 × x × y × y × y2 ) = 4x4y4
(iv) a x 2b x 3c = (1 × 2 × 3 ) (a × b × c) = 6abc

Q4: Identify the terms, their coefficients for each of the following expressions. (i) 5xyz2 – 3zy (ii) 1 + x + x2(iii) 4x2y2 – 4x2y2z2 + z2 (iv) 3 – pq + qr – p (v) (x/2) + (y/2) – xy (vi) 0.3a – 0.6ab + 0.5b

A: The answer is tabulated below: Q5: Obtain the product of
(i) xy, yz, zx
(ii) a, – a2 , a3
(iii) 2, 4y, 8y2 , 16y3
(iv) a, 2b, 3c, 6abc
(v) m, – mn, mnp

A: (i) xy × yz × zx = xyz2
(ii) a × – a2  × a= – a6
(iii) 2 × 4y × 8y2 × 16y= 1024 y6
(iv) a × 2b × 3c × 6abc = 36abc2
(v) m × – mn × mnp = –mnp

ATTEMPT CBSE CLASS 8 MATHS CHAPTER 9 MOCK TESTS

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