NCERT Solutions for Class 8 Science Chapter 16 LightNovember 26, 2020
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NCERT Solutions For Class 8 Maths Chapter 8: NCERT books are structured in a way that each chapter is followed by an exercise. Students need to go through all the topics in the chapter to be able to answer the questions in the exercise appropriately. The solution set for class 8 maths chapter 8 is prepared by a team of experts who understand the exam pattern and the marking scheme followed by NCERT. Students can follow these answers to understand the correct approach that needs to be followed to answer the questions appropriately.
CBSE Class 8 Maths Chapter 8 talks about Ratios, Converting Percentage into Fraction, Increase or Decrease in Percentage, Discounts, Tax Calculation for Purchase Goods and many more. Embibe offers 470+ practice questions for all the sub-topics of chapter 8. Students must practice all the in-text questions offered by Embibe to score good marks in the exams. Keep reading the article to know NCERT solutions for Class 8 Maths chapter 8.
Comparing Quantities may seem a bit difficult for the students to understand at first. But, practising the problems on a regular basis helps students to easily grasp the concepts and find the solutions to the problems. Students must solve as many practice questions as possible to develop proficiency in problem-solving.
Embibe offers solutions to each and every question mentioned in Class 8 Maths chapter 8 textbook considering the latest syllabus. Moreover, students can solve the problems for free at Embibe to score good marks. Embibe also offers NCERT 3D Videos, NCERT Exemplars, Embibe Explainers, etc., for free.
Below-mentioned is the list of topics present in Class 8 Maths chapter 8.
|1||Ratios and Percentages|
|2||Increase or Decrease as Per Cent|
|4||Profit and Loss|
|5||Taxes on Sale of an Item|
|7||Rate Compounded Annually or Half Yearly|
|8||Applications of Compound Interest Formula|
Some of the important points to remember for Class 8 Maths Chapter 8 have been mentioned below.
Ans: Let the money with Chameli be ₹100
Money spent by her = 75% of 100
= 75/100 × 100 = ₹75
The money left with her = ₹100 – ₹75 = ₹25
₹25 are left with her out of ₹100
₹1 is left with her out of ₹100/25
₹600 will be left out of ₹100/25 × 600 = ₹2400
Hence, she had ₹2400 in beginning.
Ans: i) Ratio of the speed of cycle to the scooter = 15/30 = 1:2
ii) Since 1 km = 1000m, so the required ratio is:
5m/10000m = 1:2000
iii) Since ₹1 = 100 paisa
₹5 = 500 paisa
So, the required ratio is 50 paise/500 paise = 1/10 = 1:10
Ans: i) 3:4 = 3/4 = 3/4 x 100/100 = 3/4 x 100% = 75%
ii) 2:3 = 2/3 = 2/3 x 100/100 = 2/3 x 100% = 66.6%
Ans: It is given that 72% of 25 students are good in mathematics.
Percentage of students who are not good in mathematics = (100 − 72)%
∴Number of students who are not good in mathematics = 28/7 x 100
Thus, 7 students are not good in mathematics.
Ans: Percentage of people who like other games = (100 − 60 − 30)%
= (100 − 90)% = 10 %
Total number of people = 50 lakh
Therefore, the number of people who like cricket = (60/100 x 50) = 30 lakh
Number of people who like football = (30/100 x 50) = 15 lakh
Number of people who like other games = (10/100 x 50) = 5 lakh
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