NCERT Solutions Class 10 Maths Chapter 13: Get Free PDF
NCERT Solutions Class 10 Maths Chapter 13: Embibe’s Mathematics experts provide NCERT Solutions for Surface Areas and Volumes to assist students in their board exam preparation. This article provides students with NCERT Solutions Class 10 Maths Chapter 13. Exercise 13.1, Exercise 13.2, Exercise 13.3, Exercise 13.4, and Exercise 13.5 are included in NCERT Solutions for Class 10 Maths Chapter 13.
We have included questions related to the chapter provided in the back as well as in other textbooks. Students can use NCERT Solutions to complete their homework and assignments on time. They can also download NCERT Solutions for Surface Areas and Volumes Class 10 for free in PDF format. Students would benefit from CBSE NCERT Solutions for Class 10 Maths Chapter 13 for board preparation as well as competitive exams such as NTSE and Olympiads.
NCERT Solutions for Class 10 Maths Chapter 13: Surface Areas and Volumes
Before getting into detailed CBSE NCERT solutions for Maths Class 10 Chapter 13, let’s have an overview of the topics and subtopics in the Surface Areas and Volumes chapter.
NCERT Solutions for Class 10 Maths Chapter 13 consists of Exercise 13.1, Exercise 13.2, Exercise 13.3, Exercise 13.4, and Exercise 13.5. Let’s have a look at the topics covered in the exercises in a tabulated manner below:
Surface Area of a Combination of Solids
Volume of a Combination of Solids
Conversion of Solid from One Shape to Another
Frustum of a Cone
Surface Area and Volume Class 10 Textbook PDF
Check out solutions of Chapter 13 Maths Class 10 below. You can also download NCERT Solutions Class 10 Maths Chapter 13 PDF to study in offline mode.
Q.1. 2 cubes each of volume 64 cm3 are joined end to end. Find the surface area of the resulting cuboid. Solution: Volume of cube =64 cm3. Let the side length of the cube be x. Then ⇒x3=64 ⇒x=4 cm
If cubes are joined end to end as shown in the adjacent figure, then the dimensions of resulting cuboid will be 4 cm, 4 cm, 8 cm. We know surface area of cuboid =2(lb+bh+lh) where l is length, b is breadth and h is height of the cuboid. Hence area of the cuboid =2(4×4+4×8+4×8) =2(16+32+32) =2×80=160 cm2
Q.2. A vessel is in the form of a hollow hemisphere mounted by a hollow cylinder. The diameter of the hemisphere is 14 cm and the total height of the vessel is 13 cm. Find the inner surface area of the vessel. Solution:
Let the radius of the cylindrical part as well as hemispherical part be r. Given the diameter of the hemisphere part is 14 cm. ⇒2r=14 ⇒r=7 cm Here we can also say height of hemisphere is 7 cm which is radius of the hemisphere. Now let the height of the cylindrical part be h. Given height of the vessel is 13 cm, Hence, height of the cylindrical part h=13-7=6 cm. We know, inner surface area of the hemisphere = 2πr2 and inner surface area of the cylinder =2πrh. Total inner surface area of the vessel = Inner surface area of the hemisphere + Inner surface area of the cylindrical part Total inner surface area of the vessel = 2πr2+2πrh. Total inner surface area of the vessel =2×227×7×7+2×227×7×6 =447+6 =572 cm2
Chapter Description: In our day-to-day life, we come across innumerable solids made up of a combination of two or more of the basic solids. You must have seen a truck with a container fitted on its back, carrying oil or water from one place to another.
Similarly, while travelling, you may have seen some big and elegant buildings or monuments made up of a combination of solids. If for some reason you wanted to find the surface areas, volumes, or capacities of such objects, how would you do it? In this chapter, you will see how to find the surface areas and volumes of such objects.
Moreover, Class 10 Maths Chapter 13 consists of Exercise 13.1, Exercise 13.2, Exercise 13.3, Exercise 13.4, and Exercise 13.5. Students will get to explore various concepts via this Chapter.
Download NCERT Solutions for Class 10 Maths for other chapters below:
Benefits of Embibe’s Surface Areas and Volumes Solution PDF
Some of the benefits of using CBSE 10 Maths Chapter 13 NCERT Solutions by Embibe are mentioned below:
All the answers in these solutions are presented in the most simple manner and easy-to-understand language so that the students can grasp the concepts without any difficulty.
NCERT Solutions by Embibe not only gives you answers but also teaches you the proper approach to solve problems.
By using the NCERT solutions for the chapter ‘Surface Areas & Volumes’, students can get well versed with the important formulas and concepts.
Our academic experts prepared the NCERT solutions according to the latest NCERT guidelines and revised CBSE syllabus. The answers to all the exercise questions in the NCERT textbook for 10th Maths are included in Embibe’s NCERT Solutions.
You can also use these Class 10 Maths Chapter 13 Textbook PDF for a quick revision of the concepts before an exam or a test. You can download the NCERT books from Embibe or the official website of NCERT.
Some of the important questions on Surface Area and Volume Class 10 PDF are listed below:
Q1: A given solid cuboidal object has the dimensions 49cm × 33cm × 24cm. It is melted and moulded into a solid sphere. Calculate the diameter of the sphere. Ans. The diameter of the sphere is 42 cm.
Q2: Can I access NCERT Solutions for Class 10 Science Chapter 13 in PDF format? Ans. Yes, you can access the NCERT Solutions for Class 10 Science Chapter 13 in PDF format. You can download the PDF from this article itself and study offline effectively.
Q3.How can I score full marks in NCERT Solutions for Class 10 Maths Chapter 13? Ans. The NCERT Solutions for Class 10 Maths Chapter 13 by Embibe website makes you reach full marks in-class tests and board exams. These solutions are essential for easy and quick revision during class tests and exams. Meanwhile, the solutions serve as the best study material for learners.
Q4: What will happen to the volume of a solid if its shape is changed from one form to another? Ans. The volume of the solid object will remain the same.
Q5: A given cone is cut in the middle through a plane that is parallel to the base of the cone. What is the name of the part left below the plane after the top part of the cone is removed? Ans. The part left is called a frustum.
Now we have provided you with all the necessary information regarding 10th Maths NCERT Solutions for Chapter 13 – Surface Area and Volumes. We also advised you to take Mock Tests on Surface Areas and Volumes. These tests are available for free at Embibe’s learning platform. These mock tests will definitely help you in securing good marks in the exam.
Embibe offers other resources along with the Surface Area and Volume Class 10 textbook PDF download. At Embibe’s learning platform, you can solve CBSE Class 10 Practice Questions or take Class 10 Mock Tests for free. Along with the solutions and sample questions, you can also refer to our article on NCERT Class 10 Textbooks to save and download Class 10 NCERT textbooks for all subjects.