JEE Main Percentile Vs Rank 2020: The National Testing Agency (NTA) conducted JEE Main 2020 January session from 6th to 9th January 2020. NTA has now released the JEE Main result for the same on 17th January 2020. The JEE Main result for the January session has been prepared based on the JEE Main normalized score which is expressed as Percentile Score (NTA Score). Neither the raw marks secured by the candidates (out of 300) nor their ranks in JEE Main 2020 January session is mentioned on the JEE Main scorecard. Only the percentile scores in each subject and the total percentile score of the candidates will be mentioned. The percentile score (NTA score) is a relative score in which the topper will get a percentile score of 100.
Students will be eager to know what their JEE Main percentile score means and what rank they are likely to get based on their percentile score. NTA will release the JEE Main ranks only after the conclusion of the April session. So, until then students won’t be able to know their JEE Main rank. To help you with this, we are providing you with the expected JEE Main Percentile vs Rank for JEE Main 2020 January session. You can bookmark this page to stay updated on all information related to JEE Main Percentile Vs Rank.
JEE Main Percentile Vs Rank 2020
The expected JEE Main Percentile Vs Rank for January session is as below:
|Percentile Scores (NTA Score)||Expected Rank|
Now you have an idea about the expected JEE Main Percentile Vs Rank. But what exactly is Percentile Score? How is Percentile calculated? How to determine the rank of the candidates from Percentile Scores?
Let’s understand all these things.
JEE Main Percentile Vs Rank 2020: What Is Percentile Score?
The Percentile Score tells how you have performed in comparison to all other students who appeared for the exam. So, it tells you what percentage of the total number of students who appeared for the exam scored less than or equal to that particular percentile in that examination. It is neither the percentage score (which is the percentage of the maximum marks that you have secured) nor the raw marks (absolute marks secured by you).
The formula to calculate percentile score is as under:
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate) / (Total number of candidates who appeared in that session).
So, with this formula, the raw marks of the candidates are normalized and expressed as Percentile Score (also called NTA Score). It also eliminates the discrepancy caused by the variation of difficulty level across various sessions.
JEE Main Percentile Vs Rank 2020: How Does Normalization Eliminate Discrepancies Caused By Variation Of Difficulty Level?
So, let us elaborate it with an example.
Let’s start with the following assumptions:
- a. Candidate A appeared for the exam in Session 1.
- b. Candidate A secured the highest marks among all the students who appeared in that Session 1. He scored 280 out of 300.
- c. A total of 45632 students appeared for the exam in Session 1.
- d. Candidate B appeared for the exam in Session 2.
- e. Candidate B secured the highest score among all the students who appeared in that Session 2. She scored 265 out of 300.
- f. A total of 45067 students appeared for the exam in Session 2.
- g. Session 1 was easier than Session 2.
Now, if we consider the raw scores secured by Candidate A (280) and Candidate B (265) to create the merit list, of course, Candidate A would be the overall topper.
That would be unfair because Session 2 was more difficult than Session 1.
Now, let’s see what happens if we normalize the scores secured by Candidate A and Candidate B using the above formula and express them in Percentile.
In Session 1:
No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate A = 45632
Total number of candidates who appeared in Session 1: 45632
Using the above formula,
Percentile Score Obtained by Candidate A = 100 x (45632/45632) = 100
In Session 2:
No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate B = 45067
Total number of candidates who appeared in Session 1: 45067
Using the above formula,
Percentile Score Obtained by Candidate A = 100 x (45067 /45067) = 100
So, you see, when expressed in Percentile, both the candidates have secured the same scores.
Let us assume the following scenarios as well:
In Session 1:
- a. Both Candidate C and Candidate D secure 2nd position with a raw score of 272
- b. Candidate E secures the 3rd position with a raw score of 255
In Session 2:
- a. Candidate F secures the 2nd position with a raw score of 255 (same as the raw score secured by the 3rd position holder of Session 1)
Now, if we consider the raw scores to compile the merit list, then the ranks of Candidates A, B, C, D, E, and F are as under:
|Candidate A (280)||1st Position|
|Candidate B (265)||3rd Position|
|Candidate C (272)||2nd Position|
|Candidate D (272)||2nd Position|
|Candidate E (255)||4th Position|
|Candidate F (2555)||4th Position|
Here, you can see that both Candidate E and Candidate F secured the same marks and hence, the same rank. But Candidate E appeared in Session 1 which was easier than Session 2. So, Candidate F should have been the one with a better rank than Candidate E. But that’s not happening because the variation in difficulty level was not considered.
So, let us look at the Percentile Scores of the candidates now:
- a. Percentile Score of Candidate C = 100 (45631/45632) = 99.9978086
- b. Percentile Score of Candidate D = 100 (45631/45632) = 99.9978086
- c. Percentile Score of Candidate E = 100 (45629/45632) = 99.9934257
- d. Percentile Score of Candidate F = 100 (45066/45067) = 99.9977811
Now, the merit list considering the Percentile Scores is as under:
|Candidate A (350)||1st Position|
|Candidate B (310)||1st Position|
|Candidate C (334)||2nd Position|
|Candidate D (334)||2nd Position|
|Candidate E (305)||4th Position|
|Candidate F (305)||3rd Position|
Here, Candidate F gets a better rank than Candidate E. So, the discrepancy in the result that would have caused if we had considered the raw scores secured by the candidates who appeared for the exam in different sessions having different difficulty level have been eliminated.
It is in this manner, the authorities calculate the JEE Main percentile scores and determine the ranks. Basically, your Percentile Score indicates the percentage of students who secured less than or equal to the raw score obtained by you.
JEE Main Percentile Vs Rank 2020: How Is The Rank Determined Using Percentile Scores?
So, as you can see, in the above example, we considered just the total Percentile Scores secured by Candidate A and Candidate B to determine their ranks. While compiling the actual JEE Main Merit List, NTA will consider the total, as well as the subject-wise Percentile scores, in the following order:
- a. Candidates who obtain a higher Total Percentile score will be given preference.
- b. If the tie still persists, candidates who obtain higher Percentile Score in Mathematics will be considered,
- c. If the tie still exists, candidates who obtain higher Percentile Score in Physics will be given preference,
- d. If the tie persists even after that, candidates who obtain higher Percentile Score in Chemistry will be considered,
- e. If the tie exists even after that, the candidate who is older (in age) will be considered,
- f. If the tie still exists after that, the candidates will be given the same rank.
Also, if the candidate appears for JEE Main in both April and January, NTA will consider the best of the two Total Percentile Score. They will not take the Subject-wise Percentile Scores into consideration.
But if the candidate appears for JEE Main either in January or in April, NTA will consider both Total and Subject-wise Percentile Scores.
JEE Main 2020
Now that the JEE 2020 January session exams are over, it is time you start preparing for your April session. JEE is one of the most important competitive exams and its preparation requires proper planning and diligence. We have brought JEE Previous Year Papers (2020) to help you in your JEE Preparation. Solving the previous year paper on Embibe will help you understand the difficulty level, syllabus coverage, ideal time for each question, questions involved with multiple concepts, repetitive nature of concepts, etc. Thus, attempt the JEE Previous Year Papers to Become Exam Ready!
Check the JEE Main 2020 question paper (January session) test links which will help you to take tests instantly.
JEE Main 2020 Question Paper – January 2020
|JEE Main 2020 Paper 7th January – Shift 1||Click Here|
|JEE Main 2020 Paper 7th January – Shift 2||Click Here|
|JEE Main 2020 Paper 8th January – Shift 1||Click Here|
|JEE Main 2020 Paper 8th January – Shift 2||Click Here|
|JEE Main 2020 Paper 9th January – Shift 1||Click Here|
|JEE Main 2020 Paper 9th January – Shift 2||Click Here|
Now, you have a clear idea about JEE Main Percentile Vs Rank. You also know how to calculate the Percentile Score or NTA Score determine the ranks. We hope it clears all your doubt regarding JEE Main normalization and JEE Main Percentile Vs Rank.
The expected JEE Main Percentile Vs Rank also gives you an idea about whether or not you are likely to get into your dream college with your current NTA Score. You can now plan your next steps accordingly.
If you are appearing for the JEE Main 2020 for the April session, revise the whole syllabus and focus more on the important chapters for JEE Main as well as your weak chapters. Solve as many JEE Main practice questions as possible and take JEE Main mock tests.
Also, with Embibe’s Artificial Intelligence-powered tool RANKUP, you can get personalized guidance for your preparation and improve on your academic weaknesses and test-taking skills. This, in turn, will guarantee your score improvement in JEE Main 2020. So, what are you waiting for?
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