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**JEE Main Percentile vs Rank 2023:** Candidates willing to get admission to the best engineering colleges through JEE Main must know about percentile vs rank. The JEE Mains percentile vs rank details will help candidates understand the JEE Main normalisation procedure. The JEE Main marks vs percentile are the percentile score corresponding to marks secured in JEE Main exam. As the exam will be conducted in multiple sessions, the JEE Main percentile score will be calculated after the normalisation process.

Once the aspirants know the expected JEE Main percentile vs rank 2023, it will assist them in devising a well-thought-out and practical exam preparation strategy. The NTA will release the final marks and percentile scores, which will be mentioned on the JEE Main scorecard. Go through this article to know the detailed information about JEE Mains percentile vs rank.

**Latest Updates**:**—** **Check JEE Main Session 1 exam analysis (live).****— NTA released the JEE Main 2023 admit card for the Session 1 exams scheduled on January 28, 29, and 30, 2023.— JEE Main Session 1 exam is being conducted from January 24, 2023 (Practice All India JEE Main mock test series 2023)**.

— JEE Main hall ticket for Session 1 released (direct link here).

— Check JEE Main 2023 guidelines here.

At Embibe, we provide the All India Test Series to help students crack JEE Main 2023 with a better score. Candidates can follow the steps below to take the AIT series:

**1st Step:**Visit the Embibe website, i.e., embibe.com.**2nd Step:**Login through your mobile number/- email.**3rd Step:**Then select your My Goal as Engineering and then choose JEE Main.**4th Step:**Click Next and select your preferred language.**5th Step:**Once done, click on the below-mentioned links to take the TEST.

Aspirants will be eager to know their JEE Main rank based on their percentile score. To help candidates with this, the academic experts of Embibe have curated JEE Mains percentile vs rank 2023 based on the past trends and the **JEE Main normalisation process**. Candidates can bookmark this page to stay updated on all JEE Mains percentile vs rank information.

Candidates can check their predicted ranks based on their JEE Main percentile. Below is the ‘marks vs percentile’ table for the reference of the JEE Main 2023 aspirants:

JEE Score Out of 300 | Predicted Ranks |
---|---|

286-292 | 19-12 |

280-284 | 42-23 |

268- 279 | 106-64 |

250- 267 | 524-108 |

231-249 | 1385-546 |

215-230 | 2798-1421 |

200-214 | 4667-2863 |

189-199 | 6664- 4830 |

175-188 | 10746-7152 |

160-174 | 16163-11018 |

149-159 | 21145-16495 |

132-148 | 32826-22238 |

120-131 | 43174-33636 |

110-119 | 54293-44115 |

102-109 | 65758-55269 |

95-101 | 76260-66999 |

89-94 | 87219-78111 |

79-88 | 109329-90144 |

62-87 | 169542-92303 |

41-61 | 326517-173239 |

1-40 | 1025009-334080 |

Now candidates can check the JEE Main predicted percentile vs rank table for an estimate of what percentile you will get based on the score:

Score Out of 300 | Percentile |
---|---|

286-292 | 99.99826992- 99.99890732 |

280-284 | 99.99617561 – 99.99790569 |

268- 279 | 99.99034797 – 99.99417236 |

250- 267 | 99.95228621- 99.99016586 |

231-249 | 99.87388626-99.95028296 |

215-230 | 99.74522293-99.87060821 |

200-214 | 99.57503767- 99.73930423 |

189-199 | 99.39319714- 99.56019541 |

175-188 | 99.02150308 – 99.3487614 |

160-174 | 98.52824811-98.99673561 |

149-159 | 98.07460288-98.49801724 |

132-148 | 97.0109678-97.97507774 |

120-131 | 96.0687115-96.93721175 |

110-119 | 95.05625037-95.983027 |

102-109 | 94.01228357-94.96737888 |

95-101 | 93.05600452 -93.89928202 |

89-94 | 92.05811248 -92.88745828 |

79-88 | 90.0448455 -91.79177119 |

62-87 | 84.56203931-91.59517945 |

41-61 | 70.26839007-84.22540213 |

1-40 | 6.66590786-69.5797271 |

Now you know about the anticipated JEE Main percentile vs rank vs marks. But what exactly is a percentile score? How is percentile calculated? How do authorities determine the ranking of candidates from percentile scores? Let us understand them one by one.

JEE Main result is declared in percentile, i.e., total and subject. The percentile score is a relative score in which the topper will get a percentile score of 100. The percentile score tells how you have performed compared to all other students who appeared for the exam.

So, it tells you what percentage of the total number of students who appeared for the exam scored less than or equal to that particular percentile in that examination. It is neither the percentage score (the percentage of the maximum marks you have secured) nor the raw marks (absolute marks secured by the candidate).

The formula to calculate the percentile score is as under:

Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) equal to or less than the candidate)/(Total number of candidates who appeared in that session) |

With this formula, the raw marks of the candidates are normalised and expressed as percentile scores (also called NTA scores). It also eliminates the discrepancy caused by the variations in difficulty levels across various sessions.

The normalisation process of JEE Main will eliminate the discrepancies caused by variations in difficulty level. We have explained the same with an example.

Let us start with the following assumptions:

- Candidate A appeared for the exam in Session 1.
- Candidate A secured the highest marks among all the students who appeared in that session. The candidate scored 280 out of 300.
- A total of 45,632 students appeared for the exam in Session 1.
- Candidate B appeared for the exam in Session 2.
- Candidate B secured the highest score among all the students who appeared in that session. The candidate scored 265 out of 300.
- A total of 45,067 students appeared for the exam in Session 2.
- Session 1 was easier than Session 2.

If we consider the raw scores secured by Candidate A (280) and Candidate B (265) to create the merit list, Candidate A would be the overall topper.

That would be unfair because Session 2 was more difficult than Session 1.

Now, let us see what happens if we normalise the scores secured by Candidate A and B using the above formula and express them in percentile.

**In Session 1:**

Number of candidates who secured a raw score Equal To or Less than Candidate A = 45,632

Total number of candidates who appeared in Session 1: 45,632

Using the above formula,

**Percentile Score Obtained by Candidate A = 100 x (45632/45632) = 100**

**In Session 2:**

Number of candidates who secured a raw score Equal To or Less than Candidate B = 45,067

Total number of candidates who appeared in Session 1: 45,067

Using the above formula,

**Percentile Score Obtained by Candidate A = 100 x (45067 /45067) = 100**

So, when expressed in percentile, it implies that both candidates have secured identical scores.

Let us assume the following scenarios as well:

**In Session 1:**

- Candidates C and D secured the second position with a raw score of 272.
- Candidate E secures the third position with a raw score of 255.

**In Session 2:**

- Candidate F secures the second position with a raw score of 255 (same as the raw score secured by the third position holder of Session 1)

Now, if we consider the raw scores to compile the merit list, then the ranks of Candidates A, B, C, D, E, and F are as under:

Candidates | Ranks |
---|---|

Candidate A (280) | 1^{st} Position |

Candidate B (265) | 3^{rd} Position |

Candidate C (272) | 2^{nd} Position |

Candidate D (272) | 2^{nd} Position |

Candidate E (255) | 4^{th} Position |

Candidate F (255) | 4^{th} Position |

Here, you can see that both Candidate E and Candidate F secured the same marks and hence, the same rank. But Candidate E appeared in Session 1, which was easier than Session 2. So, Candidate F should have been the one with a better rank than Candidate E. But that is not happening because the variation in difficulty level was not considered.

So, let us look at the percentile scores of the candidates now:

- Percentile Score of Candidate C = 100 (45631/45632) = 99.9978086
- Percentile Score of Candidate D = 100 (45631/45632) = 99.9978086
- Percentile Score of Candidate E = 100 (45629/45632) = 99.9934257
- Percentile Score of Candidate F = 100 (45066/45067) = 99.9977811

Now, the merit list considering the percentile scores is as under:

Candidates | Ranks |
---|---|

Candidate A (350) | 1^{st} Position |

Candidate B (310) | 1^{st} Position |

Candidate C (334) | 2^{nd} Position |

Candidate D (334) | 2^{nd} Position |

Candidate E (305) | 4^{th} Position |

Candidate F (305) | 3^{rd} Position |

Here, Candidate F gets a better rank than Candidate E. So, the discrepancy in the result would arise if we considered the raw scores secured by the candidates who appeared for the exam in different sessions having different difficulty levels have been eliminated.

In this manner, the authorities calculate the JEE Main percentile scores and determine the ranks. Your Percentile Score indicates the percentage of students who secured less than or equal to the raw score obtained by you.

So, as you can see, in the above example, we considered just the total percentile scores secured by Candidates A and B to determine their ranks.

The best overall (total) NTA scores will hold importance for candidates who appeared in more than one session, and the officials will consider that score. The officials will then compile the **JEE Main rank list** accordingly, and the All India Ranks JEE Main rank will be published. It can also be called the JEE Main percentile predictor.

The NTA officials have introduced two main changes in the tie-breaking rule. The age criteria which were earlier scrapped off are reintroduced. Also, preference will be given to the candidate who has applied for the JEE Main exam earlier than the other. The latest tie-breaking rules are:

**For Paper 1:**

- First preference is given to higher scores in Mathematics.
- If the scores in Mathematics are tied, then preference will be given to higher scores in Physics.
- If the tie persists, preference will be given to a higher score in Chemistry.
- If the tie is still not resolved, the candidate with less proportion of incorrect answers will be given preference, followed by
- Candidates with less proportion of incorrect answers in Mathematics will be given preference, followed by
- Candidates with less proportion of incorrect answers in Physics will be given preference, followed by
- Candidates with less proportion of incorrect answers in Chemistry will be given preference.
- If the tie is still not resolved, the older candidate will be given preference, followed by
- The applicant who has applied for the JEE Main earlier will be given preference.

**For Paper 2A:**

- First preference is given to higher scores in Mathematics.
- If the scores in Mathematics are tied, then preference will be given to higher scores in the Aptitude test.
- If the tie persists, preference will be given to a higher score in the Drawing test.
- If the tie is still not resolved, the candidate with less proportion of incorrect answers will be given preference, followed by
- Candidates with less proportion of incorrect answers in Mathematics (Part-I) will be given preference, followed by
- Candidates with less proportion of incorrect answers in the Aptitude test (Part-II) will be given preference, followed by
- If the tie is still not resolved, the older candidate will be given preference, followed by
- The applicant who has applied for the JEE Main earlier will be given preference.

**For Paper 2B:**

- First preference is given to higher scores in Mathematics.
- If the scores in Mathematics are tied, then preference will be given to higher scores in the Aptitude test.
- If the tie persists, preference will be given to a higher score in Planning-Based Questions.
- If the tie is still not resolved, the candidate with less proportion of incorrect answers will be given preference, followed by
- Candidates with less proportion of incorrect answers in Mathematics (Part-I) will be given preference, followed by
- Candidates with less proportion of incorrect answers in the Aptitude test (Part-II) will be given preference, followed by
- Candidates with fewer incorrect answers in Planning Based Questions (Part-III) will be given preference.
- If the tie is still not resolved, the older candidate will be given preference, followed by
- The applicant who has applied for the JEE Main earlier will be given preference.

Find the links for JEE Main Crash Course and Akash Tyagi’s Book below:

Sl.No. | Crash Course |
---|---|

1 | Practice Physics Crash Course |

2 | Practice Chemistry Crash Course |

3 | Practice Mathematics Crash Course |

4 | Practice Physics Express |

Here we have answered some of the most frequently asked questions regarding the JEE Mains percentile vs rank. Please take a look and get answers to all your doubts and queries.

**Ans: **The NTA officials will release the JEE Main 2023 percentile after completing both sessions on the official website.

**Ans: **Yes. A candidate who scores 70 percentile has a high chance of getting admission to the best Engineering colleges.

**Ans:*** *If your percentile is 80, it means that your marks are ahead of 80% of the total students who appeared for the exam. However, this does not help determine the number of marks because that depends on the cut-off and the overall scores of all JEE Main candidates.

**Ans: **NTA-JAB officials will convert the marks obtained by the candidate into a scale range. They use a formula to calculate the percentile score of an individual for their JEE score. Check this article for more details.

**Ans: **Aspirants looking for JEE Mains Percentile vs Rank 2023 detail can refer to this article.

*We hope this detailed article on JEE Main percentile vs rank helps you. We advise all the aspirants to gear up their preparation and finish the whole syllabus on time. Revise the topics and focus on the important chapters for JEE Main. Also, solve as many JEE Main practice questions as possible and take JEE Main mock tests at Embibe.*

**Stay tuned to Embibe for the latest updates on JEE Main percentile vs rank 2023 and more.**