**JEE Main Percentile Vs Rank 2020:** The National Testing Agency (NTA) conducted the second session of JEE Main 2020 from 1st to 6th September 2020. NTA also released the **JEE Main Answer Key** (Provisional) on September 8. Candidates were able to **calculate their probable JEE Main score** and also raise their objections against the answer key. NTA is now reviewing the challenges and making the necessary changes in the answer key. Based on the final answer key, NTA has released the **JEE Main Result** for April/September on September 11, 2020).

NTA conducted JEE Main 2020 January session from 6th to 9th January 2020 and the JEE Main result for the same was released on 17th January 2020. The JEE Main result for the January session was prepared based on the JEE Main normalized score which is expressed as Percentile Score (NTA Score). Neither the raw marks secured by the candidates (out of 300) nor their ranks in JEE Main 2020 January session was mentioned on the JEE Main scorecard. Only the percentile scores in each subject and the total percentile score of the candidates was mentioned. The percentile score (NTA score) is a relative score in which the topper will get a percentile score of 100.

With the September session concluded, the JEE Main Result will now comprise not only the total and subject-wise NTA Scores but also the rank of the candidates (considering both the sessions).

Students will be eager to know what their JEE Main percentile score means and what rank they are likely to get based on their percentile score. Until the results are declared, students won’t be able to know their JEE Main rank. To help you with this, we are providing you with the expected JEE Main Percentile vs Rank for JEE Main 2020. You can bookmark this page to stay updated on all information related to JEE Main Percentile Vs Rank.

**CHECK JEE MAIN ANSWER KEY 2020 FROM HERE**

## JEE Main Percentile Vs Rank 2020

The expected JEE Main Percentile Vs Rank 2020 is as below:

Percentile Scores (NTA Score) |
Expected Rank |

100 | 1 |

99 | 8746 |

98 | 17,490 |

97 | 26,235 |

96 | 34,980 |

95 | 43,724 |

94 | 52,469 |

93 | 61,214 |

92 | 69,959 |

91 | 78,703 |

90 | 87,448 |

85 | 1,31,171 |

80 | 1,74,895 |

70 | 2,62,342 |

60 | 3,49,789 |

50 | 4,37,236 |

40 | 5,24,682 |

30 | 6,12,129 |

20 | 6,99,576 |

10 | 7,87,023 |

5 | 8,30,747 |

0 | 8,74,469 |

Now you have an idea about the expected JEE Main Percentile Vs Rank. But what exactly is Percentile Score? How is Percentile calculated? How to determine the rank of the candidates from Percentile Scores?

Let’s understand all these things.

### JEE Main Percentile Vs Rank 2020: What Is Percentile Score?

The Percentile Score tells how you have performed in comparison to all other students who appeared for the exam. So, it tells you what percentage of the total number of students who appeared for the exam scored less than or equal to that particular percentile in that examination. It is neither the percentage score (which is the percentage of the maximum marks that you have secured) nor the raw marks (absolute marks secured by you).

The formula to calculate percentile score is as under:

Percentile Score of a Candidate = **100 x (Number of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate)/(Total number of candidates who appeared in that session).**

So, with this formula, the raw marks of the candidates are normalized and expressed as Percentile Score (also called NTA Score). It also eliminates the discrepancy caused by the variation of difficulty level across various sessions.

*Note: According to a tweet by Minister of Human Resource Development, Dr Ramesh Pokhriyal, a total of 61,366 candidates (54.67%) out of 112,247 registered candidates appeared for the exam on Day 1 (September 1). On Day 2 (September 2), 141,372 (81.08%) out of 174,350 registered candidates appeared for the exam. On Day 3 (September 3), 141,220 (82.14%) out of 171.924 registered candidates appeared for the exam.*

### JEE Main Percentile Vs Rank 2020: How Does Normalization Eliminate Discrepancies Caused By Variation Of Difficulty Level?

So, let us elaborate it with an example.

Let’s start with the following assumptions:

- a. Candidate A appeared for the exam in Session 1.
- b. Candidate A secured the highest marks among all the students who appeared in that Session 1. He scored 280 out of 300.
- c. A total of 45632 students appeared for the exam in Session 1.
- d. Candidate B appeared for the exam in Session 2.
- e. Candidate B secured the highest score among all the students who appeared in that Session 2. She scored 265 out of 300.
- f. A total of 45067 students appeared for the exam in Session 2.
- g. Session 1 was easier than Session 2.

Now, if we consider the raw scores secured by Candidate A (280) and Candidate B (265) to create the merit list, of course, Candidate A would be the overall topper.

That would be unfair because Session 2 was more difficult than Session 1.

Now, let’s see what happens if we normalize the scores secured by Candidate A and Candidate B using the above formula and express them in Percentile.

**In Session 1:**

No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate A **= 45632 **

Total number of candidates who appeared in Session 1: **45632**

Using the above formula,

**Percentile Score Obtained by Candidate A = 100 x (45632/45632) = 100**

**In Session 2:**

No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate B **= 45067 **

Total number of candidates who appeared in Session 1: **45067 **

Using the above formula,

**Percentile Score Obtained by Candidate A = 100 x (45067 /45067) = 100**

So, you see, when expressed in Percentile, both the candidates have secured the same scores.

Let us assume the following scenarios as well:

**In Session 1:**

- a. Both Candidate C and Candidate D secure 2
^{nd}position with a raw score of 272 - b. Candidate E secures the 3
^{rd}position with a raw score of 255

**In Session 2:**

- a. Candidate F secures the 2
^{nd}position with a raw score of 255 (same as the raw score secured by the 3rd position holder of Session 1)

Now, if we consider the raw scores to compile the merit list, then the ranks of Candidates A, B, C, D, E, and F are as under:

Candidate A (280) | 1^{st} Position |

Candidate B (265) | 3^{rd} Position |

Candidate C (272) | 2^{nd} Position |

Candidate D (272) | 2^{nd} Position |

Candidate E (255) |
4^{th} Position |

Candidate F (2555) |
4^{th} Position |

Here, you can see that both Candidate E and Candidate F secured the same marks and hence, the same rank. But Candidate E appeared in Session 1 which was easier than Session 2. So, Candidate F should have been the one with a better rank than Candidate E. But that’s not happening because the variation in difficulty level was not considered.

So, let us look at the Percentile Scores of the candidates now:

- a. Percentile Score of Candidate C = 100 (
) = 99.9978086*45631/45632* - b. Percentile Score of Candidate D = 100 (
) = 99.9978086*45631/45632* - c. Percentile Score of Candidate E = 100
= 99.9934257**(45629/45632)** - d. Percentile Score of Candidate F = 100
*(*= 99.9977811**45066/45067**)

Now, the merit list considering the Percentile Scores is as under:

Candidate A (350) | 1^{st} Position |

Candidate B (310) | 1^{st} Position |

Candidate C (334) | 2^{nd} Position |

Candidate D (334) | 2^{nd} Position |

Candidate E (305) |
4^{th} Position |

Candidate F (305) |
3^{rd} Position |

Here, Candidate F gets a better rank than Candidate E. So, the discrepancy in the result that would have caused if we had considered the raw scores secured by the candidates who appeared for the exam in different sessions having different difficulty level have been eliminated.

It is in this manner, the authorities calculate the JEE Main percentile scores and determine the ranks. Basically, your Percentile Score indicates the percentage of students who secured less than or equal to the raw score obtained by you.

### JEE Main Percentile Vs Rank 2020: How Is The Rank Determined Using Percentile Scores?

So, as you can see, in the above example, we considered just the total Percentile Scores secured by Candidate A and Candidate B to determine their ranks.

For candidates who appeared in both January and September sessions, the best of the two overall (total) NTA Scores will be considered. The JEE Main Merit List will then be compiled accordingly and the All India Ranks will be given.

While compiling the actual JEE Main Merit List, NTA will consider the total, as well as the subject-wise Percentile scores, in the following order:

- a. Candidates who obtain a higher Total Percentile score will be given preference.
- b. If the tie still persists, candidates who obtain higher Percentile Score in Mathematics will be considered,
- c. If the tie still exists, candidates who obtain higher Percentile Score in Physics will be given preference,
- d. If the tie persists even after that, candidates who obtain higher Percentile Score in Chemistry will be considered,
- e. If the tie exists even after that, candidates with less proportion of negative responses will be considered,
- f. If the tie exists even after that, the candidate who is older (in age) will be considered,
- g. If the tie still exists after that, the candidates will be given the same rank.

### JEE Main Preparation

JEE is one of the most important competitive exams and its preparation requires proper planning and diligence. We have brought JEE Previous Year Papers (2020) to help you in your JEE Preparation. If you are planning to appaer for JEE Main 2021, solving the previous year paper on Embibe will help you understand the difficulty level, syllabus coverage, ideal time for each question, questions involved with multiple concepts, repetitive nature of concepts, etc. Thus, attempt the JEE Previous Year Papers now!

Check the JEE Main 2020 question paper (January session) test links which will help you to take tests instantly.

**JEE Main 2020 Question Paper – January 2020**

Paper |
Test Link |

JEE Main 2020 Paper 7^{th} January – Shift 1 |
Click Here |

JEE Main 2020 Paper 7^{th} January – Shift 2 |
Click Here |

JEE Main 2020 Paper 8^{th} January – Shift 1 |
Click Here |

JEE Main 2020 Paper 8^{th} January – Shift 2 |
Click Here |

JEE Main 2020 Paper 9^{th} January – Shift 1 |
Click Here |

JEE Main 2020 Paper 9^{th} January – Shift 2 |
Click Here |

Now, you have a clear idea about JEE Main Percentile Vs Rank. You also know how to calculate the Percentile Score or NTA Score. We hope it clears all your doubt regarding JEE Main normalization and JEE Main Percentile Vs Rank.

The expected JEE Main Percentile Vs Rank also gives you an idea about whether or not you are likely to get into your dream college with your current NTA Score. You can now plan your next steps accordingly.

If you are appearing for JEE Main 2021, focus on your preparation and finish the whole syllabus on time. Revise them and focus more on the important chapters for JEE Main as well as your weak chapters. Solve as many **JEE Main practice questions** as possible and take **JEE Main mock tests**.

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*So, we hope this detailed article on JEE Main Percentile Vs Rank helps you. If you have any queries regarding JEE Main Percentile Vs Rank, drop a comment below or ping us through our Live Chat Service. We will get back to you at the earliest.*

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