JEE Main Normalization 2021: JEE Main 2021 session 4 has been conducted on August 26, 27, 31, and September 1 & 2, 2021. NTA was conducted the JEE Mains in four sessions this year – February, March, April/July, and May/August. As the exam was being conducted in four sessions, there is variation in the difficulty level of the exam across various dates and slots. Students attempting a tough paper are likely to score less than those who got an easy paper. This can result in discrepancies in the JEE Mains result and merit list/rank list.
In order to solve this problem, National Testing Agency (NTA) will normalize the raw or actual score secured by the candidate into the NTA Score (normalized score), which takes care of the variation in the difficulty level and other factors. The JEE Main Normalization process 2021 will be based on Percentile Score (Percentile Equivalence Method). This article will provide you with all the details about JEE Main 2021 Normalization Procedure and how the marks will be calculated. Read on to find out.
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Other Important Links–
|JEE Main 2021 Percentile vs Rank||JEE Main 2021 Marks vs Rank|
|JEE Mains 2021 Toppers (OUT)||JEE Main Cut off 2021|
|JEE Main 2021 Question Paper(Out)||JEE Main 2021 Answer Key (Out)|
|NIT Cut off||JEE Main 2021 Analysis (Out)|
JEE Main Normalization 2021: How to Calculate Percentile Score
Before getting into the JEE Main 2021 Normalisation process details, let us first understand what Percentile Score means.
JEE Main Normalization: What Is Percentile Score? What Is Percentile In JEE?
Percentile scores, basically, tell you how you have performed relative to all other candidates who appeared for the exam. It is not the same as your percentage score.
While the percentage score tells you the percentage of the total marks or maximum marks for the exam you have secured, the percentile score indicates the percentage of the total number of candidates appearing for the exam who have scored EQUAL TO OR LESS THAN the score you secured.
This means, in each session, the marks secured by the candidate (say, out of 300 in the case of JEE Main Paper 1) is converted into a scale ranging from 100 to 0. The topper for each session will, thus, secure a percentile score of 100.
JEE Main Normalization 2021: How To Calculate JEE Percentile?
Let us now see how JEE Main Percentile is calculated. The Percentile Score for JEE Main will be calculated using the following percentile formula:
Percentile Score of a Candidate = 100 x (Number of candidates who secured a raw score (or actual score) EQUAL TO OR LESS than the candidate)/(Total number of candidates who appeared in that session)
Let us elaborate on it with an example.
Consider the following data for a particular session of the exam:
|Number of candidates who appeared for the exam in that session||41326|
|Highest marks secured in that session||275 (out of 300)|
|Number of candidates who secured the highest marks (let’s say Candidate A)||1|
|Number of candidates who secured equal to or less than 275||41326|
|Marks secured by Candidate B in that session||121|
|Number of candidates who secured less than or equal to 121||37244|
Now, using the above formula,
Percentile Score secured by the topper, Candidate A = (100 x 41326)/41326 = 100
This means 100 percent of candidates secured less than or equal to 335, and no candidate secured more than 335.
Percentile Score secured by Candidates B = (100 x 37244)/41326 = 90.124411
This means out of the 41326 candidates who appeared for this session, 90.124411 percent of candidates secured less than or equal to Candidate B. It also means all other candidates have scored more than Candidate B.
JEE Main 2021 Normalisation Based On Percentile Score
As mentioned in the introduction, the JEE Main Normalization 2021 is based on the percentile score (or NTA score) secured by the candidates. Both subject-wise and total NTA scores are calculated for each candidate.
This reduces the chances of discrepancy in results due to variation in the difficulty level of the papers across slots. How? We will elaborate in the next section.
How Does JEE Main Normalization Eliminate Discrepancies Caused By Variation Of Difficulty Level?
So, let us elaborate on it with an example.
Let’s start with the following assumptions:
- a. Candidate A secured the highest marks among all the students who appeared in that Session 1. He scored 280 out of 300.
- b. A total of 45632 students appeared for the exam in Session 1.
- a. Candidate B secured the highest score among all the students who appeared in that Session 2. She scored 265 out of 300.
- b. A total of 45067 students appeared for the exam in Session 2.
Let us also assume that Session 1 was easier than Session 2.
Now, if we consider the raw scores secured by the two candidates, of course, Candidate A would be the overall topper.
But that would be unfair because Session 2 was more difficult than Session 1.
Now, let’s see what happens if we normalize the scores secured by Candidate A and Candidate B using the above formula and express them in Percentile.
In Session 1:
No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate A = 45632
Total number of candidates who appeared in Session 1: 45632
Using the above formula,
Percentile Score Obtained by Candidate A = 100 x (45632/45632) = 100
In Session 2:
No. of candidates who secured a raw score EQUAL TO OR LESS than Candidate B = 45067
Total number of candidates who appeared in Session 1: 45067
Using the above formula,
Percentile Score Obtained by Candidate A = 100 x (45067 /45067) = 100
So, you see, if expressed in Percentile, both Candidate A and Candidate B have secured the same scores.
Let us assume the following scenarios as well:
In Session 1:
- a. Both Candidate C and Candidate D secure 2nd position with a raw score of 272
- b. Candidate E secures the 3rd position with a raw score of 255
In Session 2:
- a. Candidate F secures the 2nd position with a raw score of 255 (same as the raw score secured by the 3rd position holder of Session 1)
Now, if we consider the raw scores to compile the merit list/rank list, then the ranks of Candidates A, B, C, D, E, and F are as under:
|Candidate A (280)||1st Position|
|Candidate B (265)||3rd Position|
|Candidate C (272)||2nd Position|
|Candidate D (272)||2nd Position|
|Candidate E (255)||4th Position|
|Candidate F (255)||4th Position|
Here, both Candidate E (of Session 1) and Candidate F (of Session 2) secured the same score and hence, have been given the same rank. But Session 1 was easier than Session 2. So, Candidate F should have been the one with a better rank than Candidate E. But that’s not happening because the variation in difficulty level was not considered.
So, let us look at the Percentile Scores of the candidates now:
- a. Percentile Score of Candidate C = 100 (45631/45632) = 99.9978086
- b. Percentile Score of Candidate D = 100 (45631/45632) = 99.9978086
- c. Percentile Score of Candidate E = 100 (45629/45632) = 99.9934257
- d. Percentile Score of Candidate F = 100 (45066/45067) = 99.9977811
Now, the JEE Main rank list/ merit list considering the Percentile Scores is as under:
|Candidate A (350)||1st Position|
|Candidate B (310)||1st Position|
|Candidate C (334)||2nd Position|
|Candidate D (334)||2nd Position|
|Candidate E (305)||4th Position|
|Candidate F (305)||3rd Position|
Here, Candidate F gets a better rank than Candidate E. So, the discrepancy that would have arisen if we had considered the raw scores of the candidates who appeared for the exam in different sessions having different difficulty level, have been eliminated.
The NTA follows the same procedure to calculate the JEE Main percentile scores (both total and subject-wise) and determine the ranks.
How Is Merit Determined In JEE Main?
The NTA will release the JEE Main February Result in this manner. For the March, April, and May sessions too, the JEE Main Result will comprise the subject-wise and overall NTA Score (Percentile Score).
For candidates who appeared in more than one session, the best overall (total) NTA Scores will be considered.
After that, NTA will compile the JEE Main Merit List and declare the All India Ranks.
In case, two or more candidates secure the same total NTA score, NTA will consider the following factors (in the same order) to determine their ranks:
a. NTA score in Mathematics,
b. NTA score in Physics,
c. NTA score in Chemistry,
d. Candidates with less proportion of negative responses,
e. Candidates older in age
If the tie exists even after applying these, candidates will be given the same rank.
JEE Mains Normalization (Percentile): How To Calculate Score PDF?
Check out the JEE Main 2021 Normalisation procedure PDF at the official website- jeemain.nta.nic.in:
The counselling and admission procedure will be based on the final merit list of the candidates.
Now you have all the details on the JEE Mains Normalisation procedure, and you also know how the NTA Score is calculated. With the release of the JEE Main Result 2021, you will get the NTA Normalized Score and your qualifying status for the JEE Advanced.
Only the top 2,50,000 candidates will be eligible for JEE Advanced, and candidates will have to qualify for this eligibility criterion. If you are qualified for JEE Advanced then, start your JEE Advanced preparation right away.
At Embibe, we also provide personalized guidance for your preparation for JEE Main. Our Artificial Intelligence-powered tool, RANKUP, provides instructions and guidance to improve your academic, behavioural and test-taking skills. This, in turn, helps in guaranteed score improvement.
FAQs on JEE Main Normalization Process 2021
Que 1: What is normalization in JEE Mains?
Ans: Normalization is introduced to compare scores secured by candidates across multi-session papers. NTA employs percentile equivalence for normalization in JEE Mains.
Que 2: How normalization is done in JEE Mains?
Ans: We have explained the normalization procedure above in this article. Candidates are advised to check the above-mentioned information for the detailed idea of JEE Mains.
Que 3: When will the JEE Mains 2021 results be announced?
Ans: NTA has already released JEE Mains 2021 session 1, 2 and 3 results. The JEE Mains session 4 result is being announced by September 14 or 15.
Que 4: When will the cutoff list for JEE Mains 2021 be released?
Ans: The cutoff list of JEE Mains 2021 will be announced along with session 4 results.
Que 5: Who conducts JEE Mains counselling?
Ans: The Joint Seat Allocation Authority (JoSSA) conducts counselling for JEE Mains. JEE mains 2021 counselling will be held in online mode. In general, JoSSA conducts JEE Mains Counseling in seven rounds.
We hope this article on JEE Main 2021 Normalization helps you. If you have any questions, feel free to ask in the comment section below. We will get back to you at the earliest.1268 Views