• Written By Shayan Patra

# NCERT Solutions for Surface Areas and Volumes Exercise 13.4 Class 10 Maths Exercise 13.4 Class 10 Maths NCERT Solutions: Chapter 13 focuses on the solids that are made up of combinations of two or more basic solids like cuboids, cones, cylinders, and spheres. Thus, students learn to calculate the surface areas and volumes of such solids in this chapter. Furthermore, Exercise 13.4 focuses on calculating the surface area and volume of the frustum of a cone.

Students can find NCERT Solutions for Chapter 13 Ex 13.4 on this page. Embibe offers free NCERT SOlutions that have solutions to all the exercise questions. Thus, students can use the solution to learn the method of solving exercise problems easily. Scroll down to check as well as download the NCERT Class 10 Maths Surface Areas and Volumes Exercise 13.4 Solutions PDF.

## NCERT Solutions for Chapter 13 Ex 13.4 Class 10 Maths: Important Topics

Candidates can find solutions to all the questions asked in Exercise 13.4 on this page. But before getting into the details of solutions, let us have an overview of the NCERT Class 10 Maths Chapter 13 topics below:

### NCERT Solutions Class 10 Maths Chapter 13 Ex 13.4: Points to Remember

NCERT Class 10 Maths Chapter 13 Exercise 13.4 has five questions on the topic “Frustum of a Cone”. In this exercise, students learn to calculate the surface area and volume of the frustum of the cone.

Suppose there is a right circular cone. If we cut a portion with a plane parallel to its base and remove the smaller cone, then the leftover part of the right circular cone is called a frustum of the cone. ‘Frustum’ is a Latin word which means ‘piece cut off’.

Let ‘h’ be the height, ‘l’ be the slant height, and ‘r1‘ and ‘r2‘ (r1 > r2) be the radius of the ends of the frustum of the cone. Thus, the formula of the volume, the curved surface area, and the total surface area of the frustum of the cone are as follows:

• Volume of the frustum of the cone = 1/3πh(r12 + r22 + r1r2)
• Curved surface area of the frustum of the cone = π( r1 + r2)l
• Total surface area of the frustum of the cone = π( r1 + r2)l + πr12 + πr22

## NCERT Solutions for Class 10 Maths: All Chapters

The detailed NCERT Class 10 Maths solutions are provided below for your reference:

Students may also check:

### FAQs on Exercise 13.4 Class 10 Maths NCERT Solutions

Find below FAQs related to Exercise 13.4 Class 10 Maths NCERT solutions:

Q: Where can I find free NCERT Class 10 Maths Exercise 14.4 Solutions?
Ans: Students can visit Embibe and download the free NCERT Class 10 Maths Solutions PDF for the Surface Areas and Volumes chapter. Embibe’s NCERT Solutions contains solutions to all the exercise questions. Thus, students can use it for their exam preparation.

Q: How many questions are there in NCERT Class 10 Maths Chapter 13 Ex 13.4?
Ans: The NCERT Class 10 Maths Surface Areas and Volumes Ex 13.4 has a total of 05 questions.

Q: What are the topics covered in the NCERT Class 10 Maths Chapter 13 Ex 13.4?
Ans: NCERT Class 10 Maths Exercise 13.4 contains questions on the topic “Frustum of a Cone”.

Q: Why should I refer to NCERT Class 10 Maths Chapter 13 Ex 13.4 Solutions at Embibe?
Ans: Embibe’s best subject matter experts have compiled the NCERT Solutions. Thus, it offers detailed solutions to all the exercise questions. Students can download the NCERT Class 10 Maths Chapter 13 Ex 13.4 Solutions PDF for free and learn the method to solve exercise questions anytime they like.

Q: What is the benefit of studying from NCERT Solutions?
Ans: NCERT Solutions provide an in-depth explanation of solving exercise question. Through NCERT Class 10 Maths Chapter 13 Ex 13.4 Solutions, students can learn the technique to solve questions whenever they get stuck while solving them.

We hope this article on NCERT Solutions for Surface Areas and Volumes Exercise 13.4 Class 10 Maths helps you. If you have any queries, leave them in the comment section below. We will surely get back to you at the earliest.

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