JEE Main Notification 2019: The National Testing Agency (NTA) has released the JEE Main 2019 exam center, date, and slots for all candidates who have successfully applied for the exam. On the official website, students need to login to their account by entering Application Number, Password and Security Pin in order to view their center, date, and slot. The JEE main Admit Card for the January session will be made available for download on 17th December 2018.
More than 800 engineering colleges in India accept JEE Main score for admission. JEE Main is also the preliminary or qualifying exam to appear in JEE Advanced which is for admission to the Indian Institutes of Technology (IITs) and some other institutes.
From 2019, JEE Main will be conducted by the NTA, the newly formed body by MHRD. NTA will conduct JEE Main twice a year – once in January and then again in April. This article will tell you all that you need to know about JEE Main 2019.
|Name of the Exam||Joint Entrance Examination – Main (JEE Main)|
|Conducting Body||National Testing Agency (NTA)|
|Category of Examination||Undergraduate Exam|
|Courses||BE / B.Tech, B.Arch/ B.Plan|
|Other Purpose of the Exam||Stage 1 for Admission to IIT
Qualifying Exam for JEE Advanced
|Exam Mode||Computer Based Test|
|Periodicity||Twice a Year (January and April)|
|Mode of Application||Online|
|Exam Duration||3 hours|
|Type of Questions||Multiple Choice Questions (MCQs)|
|Negative Marking||1 mark for wrong answer|
- JEE Mains will be conducted by NTA from 2019. CBSE will have no role left in JEE Main exam.
- JEE Mains exam will be conducted into the online mode from now.
- From 2019, The JEE Main exam will be conducted twice in a year.
- JEE Main Admit Card For 2019 Exam will be released on Dec 17, 2018.
- NTA Has released IIT PAL lecture videos to help students in their JEE Main preparation.
- Students can also practice JEE Main Mock test on the official website of NTA.
- Video lectures have been prepared by IIT Professors and subject masters of Physics, Chemistry, and Mathematics.
|Event||January Session||April Session|
|JEE Main 2019 Notification released||September 2018||February 2019|
|Availability of Application forms||September 01 to 30, 2018||February 08 to March 07, 2019|
|JEE Main Form Correction Window||October 08 to 14, 2018||March 2019|
|JEE Main 2019 Admit Card Declaration||December 17, 2018||March 18, 2019|
|JEE Main 2019 Exam Date (Paper 1 & 2)||January 06 to January 20, 2019||April 06 to April 20, 2019|
|Declaration of JEE Main 2019 Answer Key||January 2019||April 2019|
|JEE Mains Result Declaration date||January 31, 2019||April 30, 2019|
|The announcement of Qualified candidates||March 2019||May 2019|
Note that as per latest notification by the NTA, JEE Main Paper 2 of January session will be conducted on 8th January 2019 in two shifts.
It is very important that you read the JEE Mains eligibility criteria properly before you apply for JEE Main 2019.
Age Limit: For JEE Mains 2019 exam, the age limit has not been fixed.
Qualifying Exam and Subjects: Candidates must have cleared the Class 12 board exam in 2017 or 2018 or are appearing for it in 2019 with 5 subjects, including Physics, Math, and Biology/Chemistry/Technical Vocational Subject.
The number of Attempts & Year of Passing the Qualifying Exam: A student can appear for JEE Main thrice in three consecutive years. This means students who passed Class 12 exam in 2017 or 2018 and students who appeared for Class 12 exam in 2019 are eligible to appear for JEE Main 2019 both in January and April
The percentage in Qualifying Exam: For admission to NITs, IIITs, and CFTIs, candidates must score at least 75 percent (65 percent for reserved categories) in their Class 12 board exams or be in the top 20 percentile in their board exams.
|PD (with a minimum of 40 percent of Physical disability)||3 percent horizontal|
Here’s a detailed Official Notification
As mentioned above, the online registration for JEE Main 2019 – January was open from 1st of September 2018 till 30th September 2018. For the April session, the online registration will begin on 8th February 2019. The last date to apply for the April session of JEE Main is 7th March 2019.
Candidates can register themselves for the exam only in the online mode. The online application form is available on the official website of JEE Main – jeemain.nic.in.
Details Required For JEE Main 2019 Application Form
1- Aadhaar Authentication
- State of Eligibility
- State from which candidate has appeared or pass the class 12th exam (or any equivalent exam)
- Aadhar Number or Aadhar Enrollment ID
- Name of the candidate
- Date of Birth of the Candidate
2- Examination Details
- Examination center (any four)
- Paper in which a candidate Is appearing for.
3- Personal Details
- Mother’s Name
- Father’s Name
- Physical Disability or not
- Percentage of Disability (If applicable)
- Whether the candidate needs a scribe reader or not
- Place of residence
- Complete postal address along with Pin Code
4- Academic Details
- Year of Passing Class 10 exam (or any other equivalent exam)
- Place of Class 12 Schooling
- Year of appearing/ Passing Class 12 exam (or any other equivalent exam)
- Roll number QE
- Whether or not appearing Class 12 improvement exam
- Improvement exam roll number if allotted
- Name of the QE appeared/ Passed
- Type of institution for QE
- Mode of preparation
- Name and address of the school/ college from which the candidate appeared/ passed.
5- Contact Details
- E-Mail Address
- Mobile Number
- Other Numbers
6- Guardian Details
- Father’s Qualification
- Father’s Occupation
- Father’s Annual Income
- Mother’s Qualification
- Mother’s Occupation
- Mother’s annual Income
- Declaration by the candidate
- Declaration by father/ mother/ guardian
Scanned Copies To Be Uploaded
Scanned copies of candidate’s photograph, signature, and signature of their father/mother/guardian in JPEG/JPG format must be uploaded while filling up the JEE Mains application form. The size and dimension of the photograph and signatures are tabulated below:
|JEE Main 2019 Notification: Scanned Copies To Be Uploaded||File Size||Dimension|
|Photograph of the Candidate||10 kb to 200 kb||3.5 cm by 4.5 cm|
|Signature of the Candidate||4 kb to 30 kb||3.5 cm by 1.5 cm|
Follow the steps as under to apply for JEE Mains 2019:
Step 1 Go to the official website of JEE Main – jeemain.nic.in.
Step 2 Click on “Fill Application Form” and then click on “Apply For JEE Main 2019”.
Step 3 Read the instructions and click on “Proceed To Apply Online”.
Step 4 Enter your basic details, like, Name, Date of Birth, Gender, Aadhaar details, etc.
Step 5 Fill up your personal, academic, contact and exam-related details.
Step 6 Upload the scanned copies of the documents (photograph and signatures).
Step 7 Make payment of the application fee.
Step 8 Submit your application and take a print out of it for future reference.
After the online registration, candidates get the opportunity to make corrections in their application form. Candidates have to log in to their account in order to make changes/corrections in the details provided by them. However, they cannot change the exam center.
The JEE Mains correction window for the January session is over. The authorities have informed that photographs without name and date have been accepted. So, candidates won’t have to worry about that.
The JEE Mains 2019 Registration fee for different categories are tabulated below:
|Paper 1 or Paper 2 in Indian Centers||Rs 500 for General/OBC (Boys)
Rs 250 for SC/ST/PH/All Girls
|Paper 1 & Paper 2 in Indian Centers||Rs 900 for General/OBC (Boys)
Rs 450 for SC/ST/PH/All Girls
|Paper 1 or Paper 2 in Foreign Centers||Rs 2000 for General/OBC (Boys)
Rs 1000 for SC/ST/PH/All Girls
|Paper 1 & Paper 2 in Foreign Centers||Rs 3000 for General/OBC (Boys)
Rs 1500 for SC/ST/PH/All Girls
JEE Mains exam pattern will have two sets of the paper. Each paper will be divided as per the course applying. For Paper- 1, there will be 360 maximum marks in the exam and for Paper-2, maximum marks will be 390. There will be 4 marks offered for each right answer. On the other hand, 1 mark will be deducted for each wrong answer.
|Paper 1||Paper 2|
|Subjects||Mathematics, Physics, and Chemistry||Aptitude Test, Math, and Drawing|
|Question Type||Multiple Choice Questions||Multiple Choice Questions|
|Duration of the Exam||3 Hours||3 Hours|
|The language of the exam||English, Hindi and Other Regional Language||English, Hindi and Other Regional Language|
As you can see, each question carries 4 marks. 1 mark will be deducted for every wrong answer. However, there is no penalty for questions not attempted. All the questions will be of MCQ type wherein there will be four options for every question out of which only one answer will be correct.
The JEE Mains 2019 syllabus is same as the syllabus of last year. The NTA will follow the same syllabus as CBSE, i.e. the CBSE syllabus of Class 11 and 12. The detailed class-wise syllabus, i.e. JEE Main syllabus from Class 11 and Class 12 are tabulated below:
JEE Main Syllabus For Physics
|Topics From Class XI||Topics From Class XII|
|Unit, Dimension & Measurement||Geometrical Optics|
|Law of Motion||Capacitance|
|Work, Power & Energy||Current Electricity|
|Momentum & Collision||Gravitation|
|Center of Mass and Inertia||Magnetic Effects of Current and Magnetism|
|Rotational Dynamics||Nuclear Physics & Radio Activity|
|Elasticity, Calorimetry, Thermal Expansion||Communication Systems|
|Ktg & Thermodynamics||Electromagnetic Induction & AC|
|Mechanical Waves||Dual Nature of Matter and radiation.|
|Fluid Mechanics||Error in Measurement & Instruments|
JEE Main Syllabus For Chemistry
|Topics From Class XI||Topics From Class XII|
|Periodic Table & Properties||Halogen Derivative|
|Mole Concept||Co-ordination Compound|
|Nomenclature of Organic Compounds||Aromatic Hydrocarbons|
|Chemical Bondings||Aliphatic Hydrocarbons|
|Gaseous States||Liquid Solution & Surface Chemistry|
|Electronic Displacement Effect||Metallurgy|
|Redox & Equivalent Concept||Ether|
|Chemical & Ionic Equilibrium||Solid State|
|Chemical Kinetics||Carbonyl Compound|
|Radioactivity (Nuclear Chemistry)||Qualitative Analysis|
|S, P, D & F block element|
|Thermodynamic, Thermochemistry & Electrochemistry|
|Carboxylic Acids & Its Derivatives|
|Practical Organic Chemistry|
JEE Main Syllabus For Mathematics
|Topics From Class XI||Topics From Class XII|
|Logarithms & Related Expressions||Limits, Continuity & Derivebilities|
|Quadratic Equations & Expressions||Method of differentiation|
|Sequence & Progressions||Indefinite Integration|
|Compound Angles||Definite Integration|
|Trigonometric Function, Equations & Inequations||Application of Derivatives|
|Solutions of Triangles||Determinants and Matrices|
|Straight Lines & Pair of Lines||3 Dimensional Geometry|
|Permutations & Combinations||Differential Equations|
|Sets, Relations & Functions||Area Under Curve|
|Mathematical Inductions & Reasoning||Parabola, Ellipse, Hyperbola|
Since JEE Main 2019 question papers will be set up by software designed to pick up questions randomly from a question bank consisting of a large number of questions, you must have a crystal-clear knowledge of all the concepts in the syllabus. There are more than 15,000 concepts in the syllabus of JEE Mains 2019, covering all three subjects. Also, you must solve as many JEE practice questions as possible and improve your problem-solving skills.
At the same time, you need to improve your overall test-taking skills as well.
JEE Main Mock Test
More than 2000 practice centers have been set up and made operational all over India for students to practice and take tests. This will help students get used to the online platform and the test interface. Students will be able to go to the centers on Saturdays and Sundays.
You can also solve unlimited JEE practice questions and take JEE mock tests of the same level as the actual exam on Embibe for free. These are available for you 24/7.
JEE Main Admit Card
JEE Admit Card will be released on the official website. Candidates will have to log on to their account with their Registration ID / Application Number and Password and download Admit Card/Hall Ticket.
The JEE Main Admit Card will contain all the information about the candidate and the exam:
- Name of the Candidate
- Application Number
- Exam Paper
- Exam Date
- Exam Time
- Exam Center
How To Download JEE Main Admit Card
JEE Main 2019 Admit Card will be available on the official website. Following are some useful steps to download the same.
Step 1- Go on the official website of JEE Main/ NTA.
Step 2- Click on the link to download the JEE Main 2019 Admit Card.
Step 3- Enter your Application Number and Password.
Step 4- Click on Submit.
Step 5- Your admit card will appear on the screen. Save it in a safe folder. Also, take print out of your JEE Main 2019 Admit Card.
Note- Candidates must carry their admit card to the exam center without which they won’t be allowed to enter the examination hall.
JEE Main 2019 Result
JEE Main result for January exam will be declared on January 31st, 2019 whereas the result for the April exam will be declared on April 30, 2019. The procedure to download the JEE Main Result is as follows:
Step 1- Go to the JEE Main/ NTA official website.
Step 2- Click on the link to download the result.
Step 3- Enter your Application Number and Password.
Step 4- Click on Submit.
Step 5- Your result will appear on the screen. Take print out of your result for further reference.
The JEE Main scorecard will contain the following information:
- Category of the Candidate
- The nationality of the Candidate
- Subject-wise Score
- Total Score
- All India Rank
- Category Rank
JEE Main Merit List Normalization
It is clear that JEE Main Exam will be conducted into various sessions. The difficulty level of the exam will also variate. To solve this problem, the candidate’s score will be normalized and converted into percentile based on the NTA Marking Scheme. This will be done in both JEE Main January and April exams. The final merit list will be compiled based on the best of two NTA normalized scores secured by a candidate (if the candidate has appeared for the exam both the times).
In case two or more candidates secure the same NTA score, the rank will be determined considering the NTA score of the respective subjects and age in the following order:
a. NTA score of actual marks secured by the candidate in Mathematics
b. NTA score of actual marks secured by the candidate in Physics
c. NTA score of actual marks secured by the candidate in Chemistry
d. Candidates older in the age
e. Even after this criterion if the tie is not broken, candidates will be given the same rank.
The cut-off marks are the minimum marks that you must secure in the exam in order to be eligible to appear in the JEE Main counselling. The cut-off marks change every year based on various factors like:
- The total number of seats available in various NITs, IIITs, CFTIs, and other participating institutes.
- The total number of candidates appearing in the exam.
- The difficulty level of the exam.
Having knowledge of JEE Mains cutoff 2018 will give you an idea about how much you should score in order to clear the exam:
|Other Backward Categories – Non-Creamy Layer (OBC – NCL)||45|
|Scheduled Caster (SC)||29|
|Scheduled Tribe (ST)||24|
It is to be noted that clearing the cut off marks doesn’t mean you will get a seat for sure. In order to guarantee a seat, you must score as high as possible.
JEE Main Counselling 2019
The counselling process will start in the month of July 2019. The Joint Seat Allocation Authority (JoSAA) conducts the counselling. The allocation of seats is done on the basis of the JEE merit list/rank list, preference of the candidates, and the availability of seats. It is to be noted that for students who appear in JEE Main both in January and April, the best of the two scores will be considered for admission.
JEE Main Notification 2019 FAQs
Q1- What is JEE Mains?
Ans- JEE Main is the first stage of a two-stage engineering entrance exam for students seeking admissions on the graduation level. JEE Exam is being organized by IIMs each year for admissions into top engineering colleges in India like NITs, IITs etc.
Q2- What is the eligibility for JEE Main 2019?
Ans- Candidates must have cleared the Class 12 board exam in 2017 or 2018 or are appearing for it in 2019 with 5 subjects, including Physics, Math, and Biology/Chemistry/Technical Vocational Subject.
Q3- What is the difference between JEE Main Paper 1 and Paper 2?
Ans- JEE Main Paper 1 is for those students who are looking for admissions into B.tech courses among top colleges in India. It consists subject like Physics, Chemistry, and Mathematics as major subjects in the exam pattern. JEE Main Paper 2 is for the students looking for admissions into B.Arch and B.Planning courses.
Q4- What is the eligibility for IIT?
Ans- Candidates must have at least 75% in their 10+2th exam and a top cut-off score which can be varied as per various IITs. If SC/ST or Physically Handicapped, 10% of the relaxation in 10+2 score will be provided.
Q5- Is there any age limit for JEE?
Ans- As per the official notification, there is no clause of any kind of age limit in JEE Main 2019 Notification. Students appeared or appearing their 12th board exam in 2017,2018, and 2019 respectively can apply for this exam.
Q6- Can we get NIT through JEE Mains?
Ans- Yes, to be eligible for NIT counselling, it is not mandatory to score enough to be eligible for JEE advanced. So you can get NIT admission through JEE Main by clearing JEE Main exam with required rank and clearing counselling process with expected performance.
Q7- Is JEE necessary for engineering?
Ans- Nope, there are various other exams to provide engineering admissions into India. JEE is required only if you want to get admission into colleges like NITs or IITs. However, various other colleges also accept the JEE score to provide admissions.
Q8- What is the minimum age for IIT JEE?
Ans- As per the age clause, the student must be at least 17 years old to be eligible for the JEE Main exam.
Q9- How many subjects are there in JEE Main for engineers?
Ans- JEE Main will have three subjects into the exam pattern for engineering students. The paper will be known as Paper- I and will consist of Physics, Mathematics, and Chemistry.
Q 10- What is the difference between IIT and JEE?
Ans- JEE is an exam being conducted by NTA since 2019 for admissions into top engineering courses in India. While IIT is a group of colleges built by the government and which are being considered as top Indian colleges for engineering.
Q 11- Which is the largest IIT?
Ans- IIT, Kharagpur is being known as the largest IIT campus in India with 2100 acres.
Q 12- How can I study for JEE?
Ans- To study for JEE, it is advised for students to attempt mock tests, attempt question papers, Prepare the subjects chapter-wise and work on the weaker points first.
Q 13- Which is the number 1 IIT in India?
Ans- IIT Kharagpur is being considered as a topmost IIT College for engineering admissions.
You must take your JEE (Main) preparation seriously even though the exam will be conducted twice a year. You should give your best shot in the first attempt itself so that you don’t have to appear in the exam the second time or at least worry about your performance.
According to the JEE Notification, JEE Main exam will be based on the CBSE syllabus of Class 11 and 12. Students can access JEE study materials for free on Embibe. There are also innumerable free JEE practice questions available on Embibe. Embibe also provides free JEE mock tests which are of the same level as the actual exam.
It has been found that students score the same marks in the actual JEE Main exam as their score in the Embibe tests. Also, with Embibe’s Advanced Test Analysis and Personalised Guidance, Embibe guarantees score improvement.
We hope this detailed information regarding JEE (Main) Notification helps you in your JEE Main preparation. For any query related to JEE (Main) Notification/exam, drop a comment below and we will get back to you
Wishing you all the best!